Area = π × r2. Or, when you know the Diameter: A = (π/4) × D2. So A = 6π, which is 18.85. So A = 18.85. And here's the hand.
Solve for n. Round to the tenths place, if necessary. A. n = 12 B. n ≈ 9.5 C. n = 11 D. n ≈ 10.9
1 answer:
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Answer:
Step-by-step explanation:
Given:
The above triangle
Required
Solve for AB in terms of a, b and angle C
Considering right angled triangle BOC where O is the point between b-x and x
From BOC, we have that:
Make h the subject:
Also, in BOC (Using Pythagoras)
Make the subject
Substitute for h
becomes
Factorize
In trigonometry:
So, we have that:
Take square roots of both sides
In triangle BOA, applying Pythagoras theorem, we have that:
Open bracket
Substitute and
in
Open Bracket
Reorder
Factorize:
In trigonometry:
So, we have that:
Take square roots of both sides