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3 years ago

15

In the graph below, why does the graph stop increasing after 30 seconds?

1 answer:

stepladder [879]3 years ago

6 0

Answer:

The answer is "Option C".

Explanation:

It's evident from the figure below that after thirty minutes, not no more hydrogen can be created because all of the reactants have converted into products.

hydrogen gas created in cm cubes per period x = 20 seconds, y = 45 centimeters squared, and so on.

A reaction's terminus (the graph's flat line) indicates that no further products are being created during the reaction.

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A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co

algol [13]

Answer:

$\displaystyle X_T=66.6\ km$

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

$\displaystyle V_f=V_o+a\ t$

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of $0.987 m/s^2$ for 182 seconds. Then it brakes with a constant acceleration of $-0.321 m/s^2$ until it comes to a stop. We need to find the total distance traveled.

The equation for the distance is

$\displaystyle X=V_o\ t+\frac{a\ t^2}{2}$

Our data is

$\displaystyle V_o=0,a=0.987m/s^2,\ t=182\ sec$

Let's compute the first distance X1

$\displaystyle X_1=0+\frac{0.987\times 182^2}{2}$

$\displaystyle X_1=16,346.7\ m$

Now, we find the speed at the end of the first period of time

$\displaystyle V_{f1}=0+0.987\times 182$

$\displaystyle V_{f1}=179.6\ m/s$

That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0

$\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0$

$\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}$

$\displaystyle t=559.5\ sec$

Computing the second distance

$\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}$

$\displaystyle X_2=50,243.2\ m$

The total distance is

$\displaystyle X_t=x_1+x_2=16,346.7+50,243.2$

$\displaystyle X_t=66,589.9\ m$

$\displaystyle \boxed{X_T=66.6\ km}$

8 0

4 years ago

My older brother received a ticket for driving 80 mph this information describes my brothers?

Sauron [17]

Answer: 80mph describe the speed of your brother

5 0

3 years ago

A glass plate (n = 1.60) is covered with a thin, uniform layer of oil (n = 1.29). A light beam of variable wavelength from air i

frez [133]

Answer:

The thickness of the oil film is 198 nm.

Explanation:

Given that,

Refractive index of glass plate = 1.60

Refractive index of oil = 1.29

Wavelength = 511 nm

We need to calculate the thickness of the oil film

Using formula of path difference

$2nt=k\lambda$

$t=\dfrac{k\times\lambda}{2n}$

Where, n = refractive index

t = thickness

$\lambda$ = wavelength

Put the value into the formula

$t=\dfrac{1\times511\times10^{-9}}{2\times1.29}$

$t=198\times10^{-9}\ m$

$t= 198\ nm$

Hence, The thickness of the oil film is 198 nm.

7 0

4 years ago

If sugar contains 41.86% carbon and 6.98% hydrogen what percentage of sugar is oxygen?

MrMuchimi

If the only thing remaining is Oxygen then it is 51.16%.

4 0

4 years ago

Which two changes would decrease the electric force between two charged

My name is Ann [436]

Answer:

Decrease the charge of one of the particles

3 0

3 years ago