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nasty-shy [4]
3 years ago
7

A trapeze artist, with swing, weighs 800 N; he is momentarily heldto one side by his partner using a horizontal force so that th

eswing ropes make an angle of 30o with thevertical. In such a condition of static equilibrium, what isthe horizontal force being applied by the partner?

Physics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

461.88 N

Explanation:

F_{g} = Weight of the swing = 800 N

T = Tension force in the rope

F = Horizontal force being applied by the partner

Using equilibrium of force in vertical direction using the force diagram, we get

T Cos30 = F_{g}\\T Cos30 = 800\\T = \frac{800}{Cos30} \\\\T = 923.76 N

Using equilibrium of force in horizontal direction using the force diagram, we get

F = T Sin30\\F = (923.76) (0.5)\\F = 461.88 N

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You find it takes 200 J of heat to take 4 kg of an unknown substance from 200 K to 240 K. It does not change phases during this
klasskru [66]

Answer:

300 K

Explanation:

First, we have find the specific heat capacity of the unknown substance.

The heat gained by the substance is given by the formula:

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From the question:

H = 200J

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T1 = 200K

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c = 1.25 J/kgK

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If 300 J of heat is added, the new heat becomes 500 J.

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Using the same formula:

500 = 4 * 1.25 * (T2 - 200)

500 = 5 * (T2 - 200)

100 = T2 - 200

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7 0
3 years ago
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Answer:

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Explanation:

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Explanation:

:)

6 0
3 years ago
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