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nasty-shy [4]
3 years ago
7

A trapeze artist, with swing, weighs 800 N; he is momentarily heldto one side by his partner using a horizontal force so that th

eswing ropes make an angle of 30o with thevertical. In such a condition of static equilibrium, what isthe horizontal force being applied by the partner?

Physics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

461.88 N

Explanation:

F_{g} = Weight of the swing = 800 N

T = Tension force in the rope

F = Horizontal force being applied by the partner

Using equilibrium of force in vertical direction using the force diagram, we get

T Cos30 = F_{g}\\T Cos30 = 800\\T = \frac{800}{Cos30} \\\\T = 923.76 N

Using equilibrium of force in horizontal direction using the force diagram, we get

F = T Sin30\\F = (923.76) (0.5)\\F = 461.88 N

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