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2 answers:
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The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 * m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 × C
mass of electron = 9.1 × kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 × * 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m *
= 1/2 * 9.1 × *
equation both the equations
1/2 * 9.1 × *
= 1.6 ×
= 0.352 *
m/s
= 35.2 *
= 5.93 * m/s
To learn more about kinetic energy in electric field here
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Answer:
the ball will fly in AX direction, making angle of 8.84° from the motion of the car
Explanation:
Given the data in the question and as illustrated in the diagram below;
Now, Lets assume line AB represent the movement of the car,
AC is the movement of the ball been thrown back and forth in the back seat
Ax is the motion of the ball it flies off the window
so from the diagram, We can see triangle ABC
where AB is 45 mph and AC = 7 mph
and angle ∠CAB = 90°
using SOH CAH TOA
TOA; tanθ = Opposite / Adjacent
tanθ = Opposite / Adjacent
tan( ∠ ABC ) = AC / AB
we substitute
tan( ∠ ABC ) = 7 / 45
tan( ∠ ABC ) = 0.15555
( ∠ ABC ) = tan⁻¹ 0.15555
( ∠ ABC ) = 8.84°
Therefor, angle ( ∠ ABC ) is 8.84°
Meaning angle ( ∠ XAA' ) is also 8.84°
Therefore, the ball will fly in AX direction, making angle of 8.84° from the motion of the car
Answer:
The answer is B.
Explanation:
Given that the <em>current </em>(Ampere) in a series circuit is same so we can ignore it. We can assume that the total voltage is 60V and all the 3 resistance are different, 20Ω, 40Ω and 60Ω. So first, we have to find the total resistance by adding :
Total resistance = 20Ω + 40Ω + 60Ω
= 120Ω
Next, we have to find out that 1Ω is equal to how many voltage by dividing :
120Ω = 60V
1Ω = 60V ÷ 120
1Ω = 0.5V
Lastly, we have to calculate the voltage at R1 so we have to multiply by 20 (R1) :
1Ω = 0.5V
20Ω = 0.5V × 20
20Ω = 10V
