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madam [21]
3 years ago
5

The quadrilaterals ABCD and JKLM are similar. Find the length x of LM.

Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

it is 2

Step-by-step explanation:

beacause CD is quadrilateral with LM

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How do I find the critical points?
podryga [215]
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:

\frac{d}{dx}(x^{2} - 1)^{3}

So we apply chain rule:

= 3(x^{2} - 1)^{2} * 2x

Set our first derivative to zero and solve for x:

3(x^2 - 1) * 2x = 0

So we can see that (by plugging in) 0, -1 and 1 makes our solution true

So our critical value is x = 0, x = -1, x = 1
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4 years ago
Send help please!! i want to complete it asap
Nadusha1986 [10]
It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
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So to find median find cumulative frequency
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Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6

So 4.2 (median) will lie in that interval 60-70 years.
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3 years ago
Terry placed 6 numbers tiles labeled 4,7,10,11,14,21 in a box he will pick one of the number tiles from the box without looking
melisa1 [442]
Out of the 6 numbers, 3 of them are even: 4, 10, and 14. The probability that he will pick an even number is therefore 3/6 = 1/2 = .5
7 0
3 years ago
Which axiom is used to prove that the product of two rational numbers is rational
aliina [53]

Answer:

First, a rational number is defined as the quotient between two integer numbers, such that:

N = a/b

where a and b are integers.

Now, the axiom that we need to use is:

"The integers are closed under the multiplication".

this says that if we have two integers, x and y, their product is also an integer:

if x, y ∈ Z ⇒ x*y ∈ Z

So, if now we have two rational numbers:

a/b and c/d

where a, b, c, and d ∈ Z

then the product of those two can be written as:

(a/b)*(c/d) = (a*c)/(b*d)

And by the previous axiom, we know that a*c is an integer and b*d is also an integer, then:

(a*c)/(b*d)

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5 0
3 years ago
How many times does 9 go int 67
AnnZ [28]


°° Awesome question!

I'll show you how to solve this kind of question:

First, you can multiply 9 times any number to see if it's smaller than 67. If it is, it is OK to keep multiplying 9 by more numbers. Let's try this!

9 × 1 obviously equals 9, so we can keep going up.

9 × 2 = 18. Not quite there yet!

Sometimes it is OK for you to skip some numbers, Watch:

9 × 5 = 45. We can keep going. At this point you don't need to go backwards and do 9 × 3 or 9 × 4, because the products will only get farther away from 67.

9 × 6 = 54. We're getting closer!

Let's try to skip one number:

9 × 8 = 72 - HOLD UP! Oh no! We went over a little too much!

Let's try a number in between 6 and 8 - That would be 7, right?

9 × 7 = 63 - We were right on point! Obviously you can't multiply 9 by 8 again because you would get a bigger number - the 72.

__________________________________________________________

That was just one way to go about it, but there's another way, too!

You can divide 9 by 67 and see what you get. You may have a remainder, but you can just throw that out the window when we're all done:

9 ÷ 67 = 7.4444444444444444 The 4 just repeats on and on again, and we don't want that. So just throw those 4's out the window so you're left with 7.

Based on all this work, 9 goes into 67 7 times.

↑   ↑   ↑  Hope this helps! :D

4 0
4 years ago
Read 2 more answers
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