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ioda
3 years ago
6

What is 1/2 divided by 6?

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0

Answer: Fraction Form: 1/12

              Decimal Form: 0.0833

              Expanded Decimal Form: 0.08333333333

             

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

jok3333 [9.3K]3 years ago
7 0

Answer:

1/12 or 0.0833

Step-by-step explanation:

1/2 divided by 6

1/2x6

1/12!

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A proportional relationship between the number of pounds of potatoes (x) and the price in dollars (y) is graphed, and the ordere
Ronch [10]

Part A

We have x = 4 and y = 3 paired up together.

This says that 4 pounds of potatoes cost $3

The price per pound (aka unit price) is y/x = 3/4 = 0.75 dollars = 75 cents.

Answer: 75 cents per pound

========================================

Part B

The ordered pair (8,6) means x = 8 and y = 6 pair up together.

So in this case, 8 pounds of potatoes cost $6.

notice how y/x = 6/8 = 3/4 = 0.75 dollars = 75 cents here as well. So we get the same unit cost.

8 0
3 years ago
A store sells small notebooks for ​$8 and large notebooks for ​$16. If a student buys 6 notebooks and spends ​$80​, how many of
Minchanka [31]

Answer:

Small-6

Large-2

Step-by-step explanation:

small-$8

large-$16

$8×6=$48

$80-$48=$32

32÷16=2(large)

3 0
3 years ago
Is 1.5 less than 1.25
dusya [7]
I guess it’s smaller because there is a 5 and a 25 and 25 is bigger than 5
4 0
3 years ago
Which expression is equivalent to (2g^3+4)^2
Brrunno [24]

Answer:

+64g^6 + 64g^3 + 16. I think

Explanation:

{( {2g}^{3}  +4)}^{2}  = {(8 {g}^{3}  + 4) }^{2} =

(8 {g}^{3}  + 4) \times(8 {g}^{3}  + 4) = 64 {g}^{6}  + 32 {g}^{3}  + 32 {g}^{3} + 16 = 64 {g}^{6}  + 64 {g}^{3}  + 16

4 0
3 years ago
Read 2 more answers
Verify which of the following are identities.
ch4aika [34]

Answer:

C

Step-by-step explanation:

Equation 1:

1+\frac{\cos^{2} \theta}{\cot^{2} \theta(1-\sin^{2} \theta)}\\ \\ 1+\frac{\sin^{2} \theta}{\cos^{2} \theta} \\ \\ 1+\tan^{2} \theta \\ \\ \sec^{2} \theta

Equation 2:

15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cot \theta}{\csc \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\frac{\cos \theta / \sin \theta}{1/\sin \theta} \right) \\ \\ 15\cos \theta \left(\frac{1}{\cos \theta}-\cos \theta \right) \\ \\ 15\cos \theta \left(\frac{1-\cos^{2} \theta}{\cos \theta} \right) \\ \\ 15(1-\cos^{2} \theta) \\ \\ 15\sin^{2} \theta

6 0
2 years ago
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