You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Use Pythagorean theorem
a^2 + b^2 = c^2
Plug in the info
b = 53, a = 41
41^2 + 53^2 = c^2
1681 + 2809 = c^2
c^2 = 4490
Squareroot of 4490 = 67.007
Perimeter = adding all sides
53m + 41m + 67.01m = 161.01 m
Solution: 161.01 meters
Answer:
A.) 193
B.)191
C.)236
D.)128
Step-by-step explanation:
A) 12^2+(8-4)^3-15
144+(64)-15
208-15=193
B) (3*2)^3-5^2
6^3=216-5^2
216-25=191
I only showed work for A and B
Hope this helps !!
Mark brainlest please :)
The pattern is 3^(2n-2) and the next number is 3^8.
Give a brainliest please:-)
Answer:
512
Step-by-step explanation:
1st term =a
common ratio = r
a*r with the exponent n-1
a=4 r=2 n=8
8th term 4*(2 at the seventh power)= 512
OR
1st term :4
2nd term = 4*2=8
3rd term 8*2=16
4th term 12*2=32...............8th term 256*2=512
