Is this a valid conclusion? A. B. C. D.

Use substitution to solve the following system of equations. Show all of your work. Write the solution as an ordered pair.

trapecia [35]

Answer:

$\left \{ {{x=2} \atop {y=2}} \right.$

Step-by-step explanation:

Substitute the second equation into the first one:

$4x+(2x-2)=10\\6x-2=10\\6x=12\\x=2$

Substitute $x=2$ into the second equation:

$y=2\times 2-2\\y=4-2\\y=2$

$\therefore \left \{ {{x=2} \atop {y=2}} \right.$

3 0

2 years ago

Find the value of X in the simplest radical form

Galina-37 [17]

Answer:. 7

Step-by-step explanation:

4 0

3 years ago

Can you do the full work

Illusion [34]

Answer:

what full work.Everyone wants to know so we can help you.

Step-by-step explanation:

5 0

3 years ago

Time spent using e-mail per session is normally distributed, with mu equals 11 minutes and sigma equals 3 minutes. Assume that

liq [111]

Answer:

a) 0.259

b) 0.297

c) 0.497

Step-by-step explanation:

To solve this problem, it is important to know the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$