In this scenario we know that carbon14 at a given time A(t) = A0e^(-kt), where A0 is the original carbon present, t is time in years and k is the constant.
As we are working with the half life of carbon being 5730 years, we assume original carbon-14 content, A0 = 1, and carbon-14 at half life 5730 years, A(t) = 0.5.
i.e.
0.5 = 1e^(-5730k)
apply Ln to both sides of equation to cancel e
ln(0.5) = -5730k
k = ln(0.5) / -5730
k = -0.69315 / - 5730 = 1.20968 x 10^-4
The answer is 177/8 or one hundred seventy seven over eigth.
1/8(8x + 15) = 24
Multiply both sides by 8:
8* 1/8(8x + 15) = 8 * 24
8x + 15 = 192
Subtract 15 from both sides:
8x +15 - 15 = 192 - 15
8x = 177
Divide both sides by 8:
8x/8 = 177/8
x = 177/8
76 rounded to the nearest 10 is 80.
Since 6 is greater than 5, it rounds 7 to 8.
No.
2+4 is not greater than 8.
Answer:
198.43. dollars is the answer
