Answer:
Step-by-step explanation:
We would use the t- distribution.
From the information given,
Mean, μ = 2950
Standard deviation, σ = 115
number of sample, n = 25
Degree of freedom, (df) = 25 - 1 = 24
Alpha level,α = (1 - confidence level)/2
α = (1 - 0.98)/2 = 0.01
We will look at the t distribution table for values corresponding to (df) = 24 and α = 0.01
The corresponding z score is 2.492
We will apply the formula
Confidence interval
= mean ± z ×standard deviation/√n
It becomes
2950 ± 2.492 × 115/√25
= 2950 ± 2.492 × 23
= 2950 ± 57.316
The lower end of the confidence interval is 2950 - 57.316 =2892.68
The upper end of the confidence interval is 2950 + 57.316 = 3007.32
The solution is correct.
Answer:
i = 
Step-by-step explanation:
=−3+4i
4i−3=z
4i−3+3=z+3
4i=z+3
= 
Answer:
The answer is the letter B.
The first column represents the x-values, and the second row represents the y-values.
For that reason, if we have:
2x - 7y = -1
x + 3y = -5
Then, the matrix will be given by:
[ 2 -7
1 3]
Then, the third colum will be the equality:
[ -1
-5]
So the correct option is the letter B.
Answer:
what do u need help with?
Step-by-step explanation:
Theres no question. Hope this helps