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vekshin1
2 years ago
10

Sina=3/5 find cos2a​

Mathematics
1 answer:
yarga [219]2 years ago
6 0

Answer:

\huge \purple{\therefore \cos2a}  \orange{= }\red{\frac{7}{25}  }

Step-by-step explanation:

\because \cos2a =1 -  2 { \sin}^{2} a \\  \\   \therefore \cos2a =1 -  2 \bigg( {  \frac{3}{5} }\bigg) ^{2}  \\  \\\therefore \cos2a =1 -  2  \times  \frac{9}{25}   \\  \\\therefore \cos2a =1 -   \frac{18}{25}   \\  \\\therefore \cos2a =  \frac{25 - 18}{25}   \\  \\ \huge \purple{\therefore \cos2a}  \orange{= }\red{\frac{7}{25}  } \\  \\

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BARSIC [14]

Answer:

C. The number of responces p\vee q is also 46

Step-by-step explanation:

Note that:

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From the diagram,

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The formula A=P(1+r)t is used to show the total amount owed for a loan with a simple annual interest rate.
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We are asked to express r in terms of A, P, and t.

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then, dividing both sides by P, we have

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Swap the sides:

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2 years ago
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If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

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