First you do what is inside the parentheses. 10 x 5 - 3. 50 - 3 =47. Then you multiply 47 x 5 = 235.
Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Answer:
its 92 costumers
Step-by-step explanation:
Answer:
f(x) = x² - 3x - 10
Step-by-step explanation:
Given zeros x = - 2 and x = 5, then the corresponding factors are
(x + 2) and (x - 5) , so
f(x) = (x + 2)(x - 5) ← expand using FOIL
= X² - 3X - 10