Answer:
Distance swam by Sonya in 3 weeks = 19740 m
Step-by-step explanation:
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.
Number of days in 1 week = 7
Number of weeks she swam = 3
Total number of days she swam = 3 x 7 = 21 days
Distance swam per day = 0.94 km
Total distance swam = Total number of days she swam x Distance swam per day
Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m
Distance swam by Sonya in 3 weeks = 19740 m
Answer:
3
Step-by-step explanation:
<u>1) Find two corresponding lengths between the image and the pre-image</u>
Pre-image (bottom side) = 3 units
Image (bottom side) = 9 units
We can use any corresponding lengths for this step.
<u>2) Divide the length of the side from the image by the length of the side from the pre-image</u>
9 units ÷ 3 units
= 3
Therefore, the scale factor of the dilation is 3.
I hope this helps!
Answer:
y = x
Step-by-step explanation:
We can use slope-point form.
(y-y1) = m(x-x1)
m is a slope. If the line is parallel than slopes are the same.
y = x + 4, for this line slope = 1, so for line we have to find slope is also 1.
(y-y1) = m(x-x1)
m=1, x1 = 2, y1 = 2
(y - 2) = 1(x-2)
y - 2 = x - 2
y = x
arcsin(1/2) means "the angle whose sine is 1/2".
That's 30° .
y = cos(30°) = (1/2)√3 = about 0.866 .
Answer:
0
Step-by-step explanation:
If I'm not mistaken, the answer must be 0.
7-7 is 0, that cancels out
0 divided by -4w is zero. That leaves w alone
w=0. I think that's the answer.
