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Lerok [7]
3 years ago
8

A balanced hanger has 4 grapefruits and 2 plums hanging from the left side. The hanger has 3 grapefruit and 5 plums hanging from

the right side. If "g" is the weight of a grapefruit and "p" is the weight of a plum, write an equation that represents the balanced hanger.
Mathematics
1 answer:
harina [27]3 years ago
6 0

Answer:

4g + 2p = 3g + 5p :)

Step-by-step explanation:

Since the hanger is balanced we can say that the sum of plum and grapefruits on both sides are equal, hope this helps

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|20x|=2|2x+8|<br> please show all steps <br> and both answers
lukranit [14]

Step-by-step explanation:

20x = 4x +16

16x = 16

x=1

multiply the 2 into the absolute value bars. check if there are negatives. if there aren't, bars can be removed. solve as normal

7 0
3 years ago
The cost of 4 pounds of bananas is $3.52. What is the constant of proportionality that relates the cost of dollars, y, to the nu
Sladkaya [172]
.88
3.52 divided by 4
6 0
2 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
erma4kov [3.2K]

Answer:

\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

Step-by-step explanation:

Given

5 tuples implies that:

n = 5

(h,i,j,k,m) implies that:

r = 5

Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

Expand the numerator

^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

6 0
2 years ago
22. Solve the system
DaniilM [7]
Equation 1)  x + 6y = 2
Equation 2)  5x + 4y = 36

Multiply all of equation 1 by 5.

1)  5(x + 6y = 2)

Simplify.

1)  5x + 30y = 10
2)  5x + 4y = 36

Subtract equations from one another.

26y = -26

Divide both sides by 26.

y = -1

Plug in -1 for y in the first equation.

x + 6y = 2

x + 6(-1) = 2

Simplify.

x - 6 = 2

Add 6 to both sides.

x = 8

D : (8, -1)

~Hope I helped!~
8 0
2 years ago
12.4. Measure of Dispersion<br>2076 Q.No. 15 Find the standard deviation of: 4, 6, 8, 10, 12.​
Alenkinab [10]

Answer:

Standard deviation of given data = 3.16227

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Given sample size 'n' = 5

Given data  4, 6,8,10,12

Mean = \frac{4+6+8+10+12}{5} = 8

Mean of the sample x⁻ = 8

Standard deviation of the sample

                  S.D = \sqrt{\frac{Sum(x-x^{-} )^{2} }{n-1}}

<u><em>Step(ii)</em></u>:-

Given data

x          :         4      6       8       10      12

x-x⁻      :      4 - 8   6-8   8-8    10-8    12-8

(x-x⁻)   :        -4      -2     0          2        4

(x-x⁻)²  :        16     4       0         4        16  

 

  S.D = \sqrt{\frac{Sum(x-x^{-} )^{2} }{n-1}}

  S.D = \sqrt{\frac{16+4+0+4+16}{4}}

 S.D = √10 = 3.16227

<u><em> Final answer</em></u>:-

The standard deviation = 3.16227

8 0
2 years ago
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