Answer:
45
Step-by-step explanation:
Find the volume of a pyramid with a square base, where the perimeter of the base is 18.4\text{ cm}18.4 cm and the height of the pyramid is 20.6\text{ cm}20.6 cm. Round your answer to the nearest tenth of a cubic centimeter.
Answer:
Step-by-step explanation:
<h3>Part B</h3>
Assumed the dimensions of the top and bottom parts are identical.
Since the cylindrical part has total height of 1.8 cm and the hemisphere volume is transferred to bottom part and the cone part is still full, the value of h is the difference of the total height of cylinder and full part of the top section of cylinder:
- h = 1.8 cm - 0.3 cm = 1.5 cm
<h3>Part C</h3>
Find the volume of sand in the bottom part. It consists of a hemisphere and a cylinder of 1.5 cm height.
- V(cylinder) = πr²h = 3.14*(2.6/2)²*1.5 ≈ 7.96 cm³
- V(hemisphere) = 2/3πr³ = 2/3*3.14*(2.6/2)³ ≈ 4.6 cm³
<u>Total sand in the bottom part:</u>
<u>Time taken:</u>
- 12.56 / 0.05 = 251.2 seconds = 4 min 11.2 seconds
Answer:
The area of the figure is 117m²
Step-by-step explanation:
In this problem, you have two shapes. One shape is a rectangle. The other shape is a triangle.
Area of a rectangle = b*h = 9*7 = 63
Area of a triangle = 
(b*h) =
Since there are two triangles, you will multiply the area of the one triangle in the figure by 2.
27*2 = 54
Now, you add up the areas!
54 + 63 = 117
So, the area of the figure is 117m²
Answer:
c. (A + B)^2-A^2 + 2AB + B^2
Step-by-step explanation:
Given that:
a.
(A-B)^2 = A^2 - 2AB + B^2
If and only if AB = BA
Then;
(A-B)^2 = (A -B ) (A - B)
(A-B)^2 = A^2 - AB-BA + B^2 (FALSE)
b.
(AB)^2=A^2B^2
on true if any only if AB =BA
(AB)^2= (AB) (AB)
c.
(A+ B)^2 = A^2 + 2AB + B^2
(A+ B)^2 = (A + B) (A+B)
(A+ B)² = A × A + A × B + B × A + B × B
(A+ B)^2 = A^2 + A*B + B*A + B^2
This is true
