Answer:
The perimeter of the dog's play area is 30 ft
Step-by-step explanation:
Rectangle:
- The opposite sides are congruent.
- The opposite angles are congruent.
- The sum of all four angles of a rectangle is 360°.
- The sum of two adjacent angles of a rectangle is 180°.
- The diagonals bisect each other.
- The perimeter of a rectangle is = 2(Length+width)
- The area of a rectangle is = Length × width
Given that,
The length of the long side of the dog's play area was = 10 ft.
So, Length of dog's play area is = 10 ft.
The length of the short side of the dog's play area was = 5 ft.
So, width of dog's play area is = 5 ft.
It is a rectangular plot.
So, the perimeter of the dog's play area is =2(Length+width)
=2(10+5) ft
=2(15) ft
=30 ft
the two integers 87 between is 86 87 89
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.
So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.
x + 1.5 = 14
x = 12.5 ounces
The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces
x + 1.5 = 16
x = 14.5 ounces
From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
