All categories

3 years ago

Please help me !!!!!! (wrong answers get reported)

Mathematics

1 answer:

gladu [14]3 years ago

6 0

Answer:

Answer c

Step-by-step explanation:

u add 4 to the x on every one in table and which one is right in the y is the right chart

You might be interested in

Determine whether or not the given value is a solution for the equation. Answer Yes or No

igor_vitrenko [27]

Y=24 is a solution for the equation.

y/12=2 is solved by multiplying both sides by 12 to get y by itself. so you'd end up multiplying 2 • 12 which equals 24.

5 0

2 years ago

Pleaseee Help. Don't answer if you aren't going to take it serious.

Nadya [2.5K]

Stem-and-leaf plots are used for showing the frequency of which certain classes of values occur. use a stem-and-leaf plot and let the numbers themselves to show pretty much the same information. In short, they are meant to show frequencies of which numbers or values occur. Not for colors or objects.

Yes, a frequency table is a perfect way to solve the problem! These are meant to help you find the number of something that occurs, and is a simple and clean way to show your word.

6 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

D = a person has the disease

X = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

OPENER: Select all the names for the answers to a polynomial equation

alexira [117]

Roots stems finite solution

6 0

3 years ago

Determine whether the following conjecture is true or false. Give a counterexample if the answer is false.

brilliants [131]

This conjecture is false, A and C don't have to be complementary angles.

Let Angle A be 100 and Angle B be 80 degrees. They are supplementary (sum of 180).
Let Angle C be 100 and Angle B is still 80 degrees. They are supplementary.

However, Angle A and Angle C are not complementary (sum of 90).

4 0

3 years ago