All categories

2 years ago

Need help finding the measurement for x

Mathematics

1 answer:

Nataliya [291]2 years ago

6 0

Answer:

x=34

Step-by-step explanation:

x+(x+12)+(100) = 180

2x+112=180

x=68

x=34

You might be interested in

A plumber charges an initial amount,x, to make a house call plus an hourly rate,y, for the time he is working.A 1-hour job costs

Inessa05 [86]

X=$30
y=$60

1 hour job- 60x1=60+30=90
3 hour job-60x3=180+30=210

5 0

3 years ago

The Ratio of boys to girls at a middle school is 3:2. If the school has 400 people how many will be boys?

Mekhanik [1.2K]

You have to divide 400 by 5. That will equal 80. Since the ratio is 3:2 Just multiply 3 by 80 then 2 by 80! :-)

You can check it by simplifying it again.

5 0

3 years ago

Read 2 more answers

How to rewrite 11/12 in two different ways

KatRina [158]

Answer:

1) 33/36 = 11/12

2) 22/24 = 11/12

Step-by-step explanation:

Hope it helps you! Please give me Brainlest!

3 0

3 years ago

Read 2 more answers

The probability of it snowing on a given day is 4 솎<br>What is the probability of it not snowing?

Sindrei [870]

Answer:

Step-by-step explanation:

Semoga membantu anda anda sekalian

bye vangkee

6 0

3 years ago

Find the roots of the equation<br> x ^ 2 + 3x-8 ^ -14 = 0 with three precision digits

scoray [572]

Answer:

Step-by-step explanation:

Given quadratic equation:

$x^{2} + 3x - 8^{- 14} = 0$

The solution of the given quadratic eqn is given by using Sri Dharacharya formula:

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

The above solution is for the quadratic equation of the form:

$ax^{2} + bx + c = 0$

$x_{1, 1'} = \frac{- b \pm \sqrt{b^{2} - 4ac}}{2a}$

From the given eqn

a = 1

b = 3

c = $- 8^{- 14}$

Now, using the above values in the formula mentioned above:

$x_{1, 1'} = \frac{- 3 \pm \sqrt{3^{2} - 4(1)(- 8^{- 14})}}{2(1)}$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})})$

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(1)(- 8^{- 14})} - 3)$

Now, Rationalizing the above eqn:

$x_{1, 1'} = \frac{1}{2} (\pm \sqrt{9 - 4(- 8^{- 14})} - 3)\times (\frac{\sqrt{9 - 4(- 8^{- 14})} + 3}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

$x_{1, 1'} = \frac{1}{2}.\frac{(\pm {9 - 4(- 8^{- 14})^{2}} - 3^{2})}{\sqrt{9 - 4(- 8^{- 14})} + 3}$

Solving the above eqn:

$x_{1, 1'} = \frac{2\times 8^{- 14}}{\sqrt{9 + 4\times 8^{-14}} + 3}$

Solving with the help of caculator:

$x_{1, 1'} = \frac{2\times 2.27\times 10^{- 14}}{\sqrt{9 + 42.27\times 10^{- 14}} + 3}$

The precise value upto three decimal places comes out to be:

$x_{1, 1'} = 0.758\times 10^{- 14}$

5 0

3 years ago