Answer:
Step-by-step explanation:
-(1+7 x)=6x-61-7-x)=48x=36
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )
<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )
<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)
<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))
<em>z</em> = (-3 - 3<em>i </em>) / 2
Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have
arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>
arg(<em>z</em>) = arctan(1) - <em>π</em>
arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>
arg(<em>z</em>) = -3<em>π</em>/4
where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.
False because they intersect eachother if they were to continue
Answer:
Step-by-step explanation:
<h3>Solution 1</h3>
The figure (kite) is symmetric and covers half of the area of rectangle with sides 8 units aby 10 units
<u>The area of the rectangle:</u>
<u>The area of the kite:</u>
- A = 1/2*80 = 40 sq. units
<h3>Solution 2</h3>
Split the kite into two triangles and calculate their area and add up
<u>Triangle DCB has b = 8, h = 2 and has area:</u>
- A = 1/2*8*2 = 8 sq. units
<u>Triangle DAB has b = 8, h = 8 and has area:</u>
- A = 1/2*8*8 = 32 sq. units
<u>Total area:</u>
Answer:
Step-by-step explanation:
Simplify:
Move 5c to the other side:
Divide bother sides with AC:
Simplify:
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