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Liono4ka [1.6K]
3 years ago
14

The distribution of time spent brushing teeth for the 1,200 students in a school is multimodal with a mean of 43 seconds and a s

tandard deviation of 8.99 seconds. If a random sample of 9 students is selected, is it appropriate to calculate the probability of the sample mean being less than 30 seconds using an approximately Normal model? Yes, the population of 1,200 students is reasonably large in size, so the shape of the population is not a concern. Yes, the sample of 1,200 students is a reasonably large sample size, so the shape of the population is not a concern. No, it is not appropriate to estimate the probability using an approximately Normal model because the population is not Normal, and the sample size is small. No, it is not appropriate to estimate the probability using an approximately Normal model because the population is not Normal, but the sample size is reasonably large.
Mathematics
1 answer:
amm18123 years ago
7 0

Answer: c

Step-by-step explanation:

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23.6666666667

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Freddy’s savings account went from $520 to $321 after he purchased a new bike. What was the percent decrease?
Vinil7 [7]

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The bike cost $199 to get $199 you do a number line then label 520 then at the end label 321 so then you do -20 then -100 then -50 then -20 then -9. so now you add them up 20+100+50+20+9 which equals =199

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3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


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3 years ago
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