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yKpoI14uk [10]
2 years ago
11

What is x+x+x+2? Choose 2 answers in khan academy

Mathematics
1 answer:
ddd [48]2 years ago
8 0

Answer:

A and d

Step-by-step explanation:

because x has a 1 in front of them so add the 3'x and get 3x+2

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3x-y+z=-15<br> x+2y-z=1<br> 2x+3y-2z=0
Kazeer [188]
I assume you are being asked to solve these equations.  Since there wasn't an explanation as to how you are expected to solve them, I chose to demonstrate how to use a calculator matrix function. You can find matrix calculators online.  My instructions are for a TI-84
Push the blue 2nd button then push x^-1 button (it says matrix above this button in blue)
Arrow over to edit to change the dimensions of the matrix and to put in your values.  You have 3 equations (3 rows) and 4 terms (4 columns) so you put a 3x4 in for the dimension and the coefficients (see images).
You use the rref option in the math column in matrix to calculate the answer. 
The numbers at the end are the solutions. x = -4, y = 2, z = -1

5 0
4 years ago
Factorize (2a-b)^2 -4(2a-b) -13
SpyIntel [72]

Answer:

Hello!

`~~~~~~~~~~~~`

(2a-b)^2 -4(2a-b) -13 =

v = 4a^{2} - 4ab + b^{2} - 8a +4b - 13

~~~~~~~~~~~~`

Step-by-step explanation: All you have to do is Factor the polynomial.

Hope this helped you. Brainliest would be nice!

______________❤︎______________

6 0
3 years ago
+16-(24)+(-8+6)-(-12+4)=???
cupoosta [38]

16 - (24) + (-8 + 6) - (-12 + 4) =

-8 + (-8 + 6) - (-12 + 4) =

-8 + (-2) - (-12 + 4) =

-10 - (-12 + 4) =

-10 - (-8) =

-10 + 8 =

-2

Hope this helps!

8 0
3 years ago
Read 2 more answers
Please Help!! These are 3 seperate questions I need help with.
Brums [2.3K]

Answer:

  1. A.  (x1, x2) = (1, 4)
  2. C.  There is no solution.
  3. B.  The solutions are of the form: (x1, x2, x3) = (4t+4, t-3, t)

Step-by-step explanation:

1.  Subtract the first equation from twice the second to eliminate x2.

  2(2x1 -x2) -(x1 -2x2) = 2(-2) -(-7)

  3x1 = 3 . . . . . simplify

  x1 = 1 . . . . . . .divide by 3

Substitute this value into the second equation.

  2·1 -x2 = -2

  4 -x2 = 0 . . . . . add 2

  4 = x2 . . . . . . . add x2

The solution is (x1, x2) = (1, 4).

__

2. Multiply the first equation by 3 and add the second equation.

  3(-5x1 -3x2) +(15x1 +9x2) = 3(7) +(2)

  0 = 23 . . . . . not true;

There is no solution.

__

3. There are two equations in 3 unknowns, so there cannot be a unique solution. The equations are not dependent, so there will be an infinite number of solutions that can be written in terms of a single parameter (t).

Let x3 = t. Then the system of equations can be rewritten as

  2x1 - 5x2 = 23 +3t

  x1 - 4x2 = 16

Subtracting twice the second equation from the first, we have ...

  (2x1 -5x2) -2(x1 -4x2) = (23 +3t) -2(16)

  3x2 = 3t -9 . . . simplify

  x2 = t -3 . . . . . divide by 3

Substituting this into the second equation above, we have ...

  x1 -4(t -3) = 16

  x1 = 16 +4t -12 . . . . . . add 4(t-3)

  x1 = 4t +4 . . . . . . . . simplify

The solutions are (x1, x2, x3) = (4t+4, t-3, t).

_____

The attachment shows the first system solved by graphical means. This validates our answer.

7 0
4 years ago
What does (0,0) represent in terms of the situation
iris [78.8K]
That tepersents that there will not be anythjng in the front
7 0
3 years ago
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