<u>Answer:</u>
Below!
<u>Explanation:</u>
Exponents are small numbers that defines how many times does the base needs to multiply itself. Two exponents can also be classified in words. 'Squared' defines a number multiplying itself two times. 'Cubed' defines a number multiplying itself three times. If there is a zero as the base's exponent, this means that the result will always be 1. Now, let's solve all the problems together.
- 2¹ = 2
- 3⁵ = 3 x 3 x 3 x 3 x 3 = 243
- 4³ = 4 x 4 x 4 = 64
- 6⁴ = 6 x 6 x 6 x 6 = 1256
- 7⁴ = 7 x 7 x 7 x 7 = 2401
- 1⁶ = 1 x 1 x 1 x 1 x 1 x 1 = 1
- 8² = 8 x 8 = 64
- 2³ = 2 x 2 x 2 = 8
- 4⁴ = 4 x 4 x 4 x 4 = 256
- 10³ = 10 x 10 x 10 = 1000
- 12² = 12 x 12 = 144
- 5⁴ = 5 x 5 x 5 x 5 = 625
- 6² = 6 x 6 = 36
- 3⁶ = 3 x 3 x 3 x 3 x 3 x 3 = 729
- 7³ = 7 x 7 x 7 = 343
- 2⁴ = 2 x 2 x 2 x 2 = 16
- 11⁰ = 1
- 4³ = 4 x 4 x 4 = 64
- 1¹² = 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 x 1 = 1
Hoped this helped!
Circumcenter is the one among the following choices given in the question that may fall outside a triangle. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer you were looking for and it has come to your help.
Answer:
A. 85
Step-by-step explanation:
The answer is 30
40 times 3/4 is 30
40 times .75 is also 30
Answer: A: 0.0031
Step-by-step explanation:
Given : In a study of wait times at an amusement park, the most popular roller coaster has a mean wait time of 17.4 minutes with a standard deviation of 5.2 minutes.
i.e. 
and 
We assume that the wait times are normally distributed.
samples size : n= 30
Let x denotes the sample mean wait time.
Then, the probability that the mean wait time is greater than 20 minutes will be :
![P(x>20)=1-P(x\leq20)\\\\=1-P(\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}\leq\dfrac{20-17.4}{\dfrac{5.2}{\sqrt{30}}})\\\\=1-P(z\leq2.74)\ \ [\because\ z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=1-0.9969\ \ [\text{ By z table}]\\\\=0.0031](https://tex.z-dn.net/?f=P%28x%3E20%29%3D1-P%28x%5Cleq20%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5Cleq%5Cdfrac%7B20-17.4%7D%7B%5Cdfrac%7B5.2%7D%7B%5Csqrt%7B30%7D%7D%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq2.74%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3D1-0.9969%5C%20%5C%20%5B%5Ctext%7B%20By%20z%20table%7D%5D%5C%5C%5C%5C%3D0.0031)
Hence, the probability that the mean wait time is greater than 20 minutes.= 0.0031
Thus , the correct answer is A: 0.0031 .
