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ASHA 777 [7]
3 years ago
15

PLEASE HELP mE: Expand the expression 0.9(7x - 1) + 9?

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
8 0

Answer:

6.3x+8.1 simplify

Step-by-step explanation:

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a restaurant owner bought 4 boxes of disposable cups for $145 , with each box containing 1,656 cups. if he wanted to divvy up th
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1104 cups per 1 restaurant

There are FOUR boxes EACH containing 1656 cups, MEANING that you will do 1656 x 4, getting 6624.

You divide this by 6, and TADA!

Hope this helps!
5 0
3 years ago
Write an expression that represent the product of q and 8, divided by 4
igomit [66]
Q8 (division sign) 4


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8 0
3 years ago
Read 2 more answers
What value of y satisfies the system of equations below?<br> 2x - y = 6<br> 2x + 3y = 14
Oksana_A [137]

Answer: y=2

Step-by-step explanation:

2x+3y=14 - 2x-y=6 = 4y=8

y=2

If you need x, just insert y into the equation and work out x from there

2x-2=6

2x=8

x=4

5 0
2 years ago
Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh
yuradex [85]

Answer:

The northern lighthouse is approximately 24.4\; \rm mi closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as \rm N, the southern lighthouse as \rm S, and the boat as \rm B. These three points would form a triangle.

It is given that two of the angles of this triangle measure 40^{\circ} (northern lighthouse, \angle {\rm N}) and 21^{\circ} (southern lighthouse \angle {\rm S}), respectively. The three angles of any triangle add up to 180^{\circ}. Therefore, the third angle of this triangle would measure 180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ} (boat \angle {\rm B}.)

It is also given that the length between the two lighthouses (length of \rm NS) is 75\; \rm mi.

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, \angle {\rm B} is opposite to side \rm NS, whereas \angle {\rm S} is opposite to side {\rm NB}. Therefore:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}.

Substitute in the known measurements:

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}.

Rearrange and solve for the length of \rm NB:

\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}.

(Round to at least one more decimal places than the values in the choices.)

Likewise, with \angle {\rm N} is opposite to side {\rm SB}, the following would also hold:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}.

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}.

\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}.

In other words, the distance between the northern lighthouse and the boat is approximately 30.73\; \rm mi, whereas the distance between the southern lighthouse and the boat is approximately 55.12\; \rm mi. Hence the conclusion.

4 0
2 years ago
Need help question 11
Helga [31]
I am sorry i dont understand

5 0
2 years ago
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