Question

Find the equation of the line that is perpendicular to the given line and passes through the given point. Enter your answer in slope-intercept form (y = mx + b) with the values of m and b given as decimals, rounded to the nearest hundredth if necessary. y = 5x ; (6, −7)

Answer 1

Answer:

y = -0.2x - 5.8

Step-by-step explanation:

If a line is given in the form y = mx + b, the "m" is the slope.

For the line given y = 5x, the slope is 5

The line that is perpendicular to this will have slope that is "negative reciprocal of that".

So, the perpendicular line will have slope of  $-\frac{1}{5}$

So, the Perpendicular Line will have equation:

y = -1/5x + b

Let's find b by replacing x with 6 and y with -7 [the point given]. So we have:

$y=-\frac{1}{5}x+b\\-7=-\frac{1}{5}(6)+b\\-7=-\frac{6}{5}+b\\b=-7+\frac{6}{5}\\b=-5.8$

So the equation of perpendicular line = y = -0.2x - 5.8