What is the domain of y = √x^2-1?

2 answers:

7 0

X can be -1 or 1 for the square root to be 0

The correct option is a

5 0

$y=\sqrt{x^2-1}\\\\The\ domain:\\\\x^2-1\geq0\ \ \ |+1\\\\x^2\geq1\iff x\geq1\ \vee\ x\leq-1\to|x|\geq1\\\\Answer:\ a.\ |x|\geq1$

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