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3 years ago

What is the domain of y = √x^2-1?

Mathematics

2 answers:

andriy [413]3 years ago

7 0

X can be -1 or 1 for the square root to be 0

The correct option is a

Reptile [31]3 years ago

5 0

$y=\sqrt{x^2-1}\\\\The\ domain:\\\\x^2-1\geq0\ \ \ |+1\\\\x^2\geq1\iff x\geq1\ \vee\ x\leq-1\to|x|\geq1\\\\Answer:\ a.\ |x|\geq1$

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Which of these problem types can not be solved using the Law of Sines?

andrezito [222]

I think the answer is B!

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6 0

3 years ago

I need help with this problem. Please!

Leviafan [203]

The first blank is 69 degrees

6 0

3 years ago

Mr. Abaya goy P700,000 loan for the expansion of his business payable monthly in 4years. How much os the monthly amortization if

Vaselesa [24]

The monthly amortization is P23,511.63

<h2>Compound interest</h2>

The formula for calculating the compound interest is expressed as:

$A = P(1+r/n)^t$

whrere:

P is the principal = P700,000
r is the rate = 12% = 0.12
t is the time = 4 years
n = 12

Substitute the parameters

$A = 700000(1+0.12/12)^{4(12)}\\
A = 700,000(1.01)^{48}\\
A =1,128,558.25$

Calculate the monthly payment:

Monthly payment = $\frac{1,128,558.25}{48} =23,511.63$

Hence the monthly amortization is P23,511.63

Learn more on compound interest here: brainly.com/question/24924853

8 0

2 years ago

The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 10^7 kilometers, and the distance of Earth from the Sun is 1.

lukranit [14]

Answer: 9.2•10^7 kilometers

Step-by-step explanation:

5.8•10^7=58,000,000

1.5•10^8=150,000,000

150,000,000-58,000,000=92,000,000

92,000,000=9.2•10^7

4 0

3 years ago

The part of a cylindrical soup can that is covered by the label is 8.5 cm tall and has a diameter of 6.5 cm. What is the area of

julia-pushkina [17]

Answer:

$180.4~cm^2$

Step-by-step explanation:

<u>Surface Area</u>

The surface area of a cylinder of height h and radius r is given by:

$A=2\pi rh$

It only covers the lateral side of the cylinder. If both the top and the bottom sides are to be included, then:

$A=2\pi rh+2\pi r^2$

The label will cover only the lateral side of the soup can that has a height of h=8.5 cm and a diameter of 6.5 cm. We need to calculate the radius which is half of the diameter r=6.5 cm / 2 = 3.25 cm.

Now we calculate the side area of the can:

$A=2\pi (3.25)(8.5)$

$A=173.6~cm^2$

We need to add the 0.8 cm overlap to the total area already calculated. This overlap has 0.8 cm of width and 8.5 cm of height, so this overlap area is:

$A_o= 0.8*8.5=6.8~cm^2$

The total area of the label is:

$A=173.6~cm^2+6.8~cm^2=180.4~cm^2$

The area of the label is $\mathbf{180.4~cm^2}$

5 0

3 years ago