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Solnce55 [7]
2 years ago
8

Please help!!!! 2 questions 50 points!!!!

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
7 0

Answer:

See below ~

Step-by-step explanation:

<u>Question 1</u>

<u>The missing angles</u>

  • Both the unknown angles have the same value as the other two angles in the triangles are the same
  • ∠(missing) = 180 - (72 x 2)
  • ∠(missing) = 180 - 144
  • ∠(missing) = 36°

⇒ The sides are <u>equal</u>

⇒ Angles are <u>not 90°</u>

⇒ It is a <u>rhombus</u>

<u></u>

<u>Question 2</u>

  • The <u>diagonals</u> of the shape <u>bisect other</u> (Statement 1)
  • NY = NW (given)
  • XN = NZ (given)
  • ∠XNY = ∠WXZ (vertically opposite angles)
  • ΔXNY ≅ ΔWXZ (SAS)
  • They form <u>two congruent triangles</u> (Statement 2)
  • From these two statements, it is evident the figure is a <u>parallelogram</u>
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Answer:

Sean is 1.15m

Step-by-step explanation:

35cm = 0.35m

Lisa is 1.5m tall and Sean is 0.35m shorter

1.5m - 0.35m = 1.15m

Sean is 1.15m

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Step-by-step explanation:

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3 years ago
What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

6 0
2 years ago
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