Deductive reasoning involves making broad observations and examining possibilities to reach a specific, logical conclusion, which is required in the formation of a hypothesis. Conversely, inductive reasoning involves taking specific observations and making broad generalisations from these. Therefore the answer is A.
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Glucose is a molecular substance therefore, there are no ionic species in glucose.
Ionic substances dissolve in water to yield ions. Molecular substances do not produce ions in solution. The conductivity of ionic solutions owes to the presence of ions in solutions. Molecular solutions do not conduct electricity due to the absence of ions.
Glucose is a molecular substance hence they are are no ions present hence glucose does not conduct electricity.
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Answer:
0.16 moles of Ar
Explanation:
One mole is equal to 6.022×10^23 atoms
9.63 x 10^22 atoms * 1 mol/6.022×10^23 atoms = 0.15991364995 moles
Answer is: mass of the ore is 8.54kg.<span>
</span>ω(Ca₃(PO₄)₂ - calcium phosphate) = 58.6% ÷ 100% = 0.586.
m(P) = 1.00 kg · 1000 g/kg.
m(P) = 1000 g.
In one molecule of calcium phosphate there are two phosphorus atoms:
M(Ca₃(PO₄)₂) = 310.18 g/mol.
M(P) = 30.97 g/mol.
For one kilogram of phosphorus, we need:
M(Ca₃(PO₄)₂) : 2M(P) = m(Ca₃(PO₄)₂) : m(P).
310.18 g/mol : 61.94 g/mol = m(Ca₃(PO₄)₂) : 1000 g.
m(Ca₃(PO₄)₂) = 5007.75 g ÷ 1000 g/kg = 5.007 kg.
Mass of ore find from proportion:
m(Ca₃(PO₄)₂) : m(ore) = 56% : 100%.
m(ore) = 100% · 5.007 kg ÷ 58.6%.
m(ore) = 8.54kg.
<u>Answer:</u> D. the ionic compound calcium fluoride
The correct option here is the fourth one.
<u>Explanation:</u>
Salt like compounds addition to water is likely to be inducing certain changes in temperature of freezing into solid and also alter the temperature of boiling.
It is noticed that addition of salts in water mostly tends to get lower the freezing temperatures from the original freezing point of water and among the given 3 options calcium fluoride tends to lower the freezing point most when compared to others.
Thus as vant hoff factor is highest factor for and the freezing point will be lowest.