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Ipatiy [6.2K]
3 years ago
15

A solution at 25 degrees Celslus 1.0*10^ -5 MH 3 O^ + . What the concentration of OH^ - in this solution?

Chemistry
1 answer:
dexar [7]3 years ago
7 0

Answer:

D.

Explanation:

-log(1.0x10^-5) = pH

pH + pOH = 14 (rearrange it)

OH- = 10^-pOH = 1.0 x 10^-9

- Hope that helped! Let me know if you need further explantion.

You might be interested in
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately to 4 significant fi
zmey [24]

Answer:

Average density for method A = 2.4 g/cm³

Average density for method B = 2.605 g/cm³

Explanation:

In order to calculate the average density for each method, we need to add the data for each method, and then divide the result by the number of measurements (in this case is 4 for both methods):

  • For Method A:

Σ = 2.2 + 2.3 + 2.7 + 2.4 = 9.6

Average = 9.6/4 = 2.4 g/cm³

  • For Method B:

Σ = 2.603 + 2.601 + 2.605 + 2.611 = 10.420

Average = 10.420/4 = 2.605 g/cm³

5 0
3 years ago
What is the volume in L of 3.8 kg of this liquid?
DedPeter [7]
1L ------------ 1 kg
? ------------- 3.8 kg

3.8 x 1 / 1

= 3.8 L
4 0
3 years ago
Is this correct im so confused.
inysia [295]

Answer:

<em>the last option!!!!</em>

Explanation:

because its right

4 0
3 years ago
Which of the changes of state shown in the model happen when thermal energy is added
AysviL [449]

Answer:

sublimation

Explanation:

immediately into a gas when thermal energy is added to it. The process is called sublimation. Sublimation is the change of state from a solid to a gas without going through the liquid state.

3 0
3 years ago
A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0
3 years ago
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