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ELEN [110]
3 years ago
9

A bicyclist at the top of a hit begins to coast without pedaling. The bicycle speeds up as it descends to the bottom of the hill

and then slows down as it continues
up a second, where it stops. Which of these sequences best describes the energy change of the bicycle from the top of the hill until it stops?

A.potential - kinetic-kinetic

B.Kinetic -potential -potential

C.Kinetic -potential -Kinetic

D.potent - Kinetic -potential
Physics
1 answer:
antiseptic1488 [7]3 years ago
5 0
It goes potential, then kinetic, then potential. So D.
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pav-90 [236]

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8 0
3 years ago
Read 2 more answers
1. Write the following degrees in radian measure
svp [43]
C is the right answer

I hooe this helps
6 0
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The rho− meson has a charge of −e, a spin quantum number of 1, and a mass 1 507 times that of the electron. The possible values
Inessa [10]

Answer:

Look up attached file

Explanation:

6 0
3 years ago
One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra
sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration (a_{r}), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

a_{r} = 4\pi^{2}\cdot f^{2}\cdot R (1)

Where:

f - Frequency, measured in hertz.

R - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension (T), measured in newtons, through the string, then we derive the following model:

\Sigma F = T = m\cdot a_{r} (2)

Where m is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right) (4)

\frac{T_{2}}{T_{1}} = 4\cdot 2

\frac{T_{2}}{T_{1}} = 8

If both the radius and frequency are doubled, then the tension is increased 8 times.

5 0
3 years ago
Suppose a log's mass is 5kg. After burning, the mass of the ash is 1 kg. Explain what could have happened to the other 4kg.
snow_lady [41]
Mass never just disappears. The other 4kg had to go somewhere. It could have left the scene of the fire in the form of smoke particles and hot gases.
3 0
4 years ago
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