A mechanic turns a wrench using a force of 27.00 N at a distance of 16.00 cm from the rotation axis. The force is perpendicular
1 answer:
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Answer:
1. the electric potential energy of the electron when it is at the midpoint is - 2.9 x J
2. the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge is - 5.04 x J
Explanation:
given information:
= 3 nC = 3 x
C
= 2 nC = 2 x
C
r = 50 cm = 0.5 m
the electric potential energy of the electron when it is at the midpoint
potential energy of the charge, F
F = k
where
k = constant (8.99 x )
electron charge, = - 1.6 x
C
since it is measured at the midpoint,
r =
= 0.25 m
thus,
F =
= k + k
= (
)
= (8.99 x )( - 1.6 x
)(3 x
+2 x
)/0.25
= - 2.9 x J
the electric potential energy of the electron when it is 10.0 cm from the 3.00 nC charge
= 10 cm = 0.1 m
= 0.5 - 0.1 = 0.4 m
F = k + k
= (
+
)
= (8.99 x )( - 1.6 x
)(3 x
/0.1+2 x
/0.4)
= - 5.04 x J
Answer:
x = 2.044 m
Explanation:
given data
initial vertical component of velocity = Vy = 2sin18
initial horizontal component of velocity = Vx = 2cos18
distance from the ground yo = 5m
ground distance y = 0
from equation of motion
solving for t
t = 1.075 sec
for horizontal motion
x = 2cos18*1.075
x = 2.044 m
Answer:
5.5x 10^-11 C
Explanation:
Pls see attached file
