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3 years ago

Deduced hydrochloric acid is a strong acid

Physics

1 answer:

Zina [86]3 years ago

7 0

Answer:

for real? i never knew that!:)

Explanation:

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a freight train travels at v=60(1-e^-t) ft/s, where t is the elapsed time in seconds. Determine the distance traeled in tree sec

lesantik [10]

Answer

given,

$v = 60(1-e^{-t})\ ft/s$

t = 3 s

we know,

$v = \dfrac{dx}{dt}$

$a = \dfrac{dv}{dt}$

position of the particle

$dx = v dt$

integrating both side

$\int dx =\int 60(1-e^{-t}) dt$

$x = 60 t + 60 e^{-t}$

Position of the particle at t= 3 s

$x = 60\times 3+ 60 e^{-3}$

x = 182.98 ft

Distance traveled by the particle in 3 s is equal to 182.98 ft

now, particle’s acceleration

$a = \dfrac{dv}{dt}$

$a = \dfrac{d}{dt}60(1-e^{-t})$

$a = 60 e^{-t}$

at t= 3 s

$a = 60 e^{-3}$

a = 2.98 ft/s²

acceleration of the particle is equal to 2.98 ft/s²

7 0

4 years ago

a car with an initial velocity of 10ms north was accelerated for 6 second until it ha a final velocity of 25ms north, what is th

koban [17]

Answer:

2 1/2 m/s^2 or 2.5m/s^2

Explanation:

From the question

final velocity v =25m/s

Initial velocity u =10m/s

time = 6 seconds

acceleration a = ?

Using the equation for linear motion

v = u + at

25 = 10 + a x 6

25 = 10 + a6

Subtract 10 from both sides

25-10 = 10 + a6 -10

25 - 10 = 10 -10 + a6

15 = a6

Divide both sides by 6

15/6 = a6/6

5/2 = a

a = 2 1/2 m/s^2 or 2.5m/s^2

8 0

3 years ago

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If a body with a mass of 4 kg is moved by a force of 20 N, what is the rate of its acceleration?

valentina_108 [34]

Explanation:

F = ma

20 N = (4 kg) a

a = 5 m/s²

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3 years ago

A _________ reaction is a type of endothermic reaction that takes place when an ionic compound mixes in water to create an ionic

USPshnik [31]

Chemical reaction is a type of endothermic reaction.

5 0

4 years ago

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The 6 kg block is then released and accelerates to the right, toward the 4 kg block. The surface is rough and the coefficient of

KatRina [158]

Answer:

v =3.41 m/s

Explanation:

given,

mass of block 1 = 6 Kg

mass of another block 2 = 4 Kg

coefficient of friction = 0.3

Assuming 6 Kg block is attached to the spring of spring constant 350 N/m

and distance between the two block is equal to 0.5 m

using formula

$U = \dfrac{1}{2}kx^2$

$U = \dfrac{1}{2}\times 350 \times 0.5^2$

U = 43.75 J

using conservation of energy

KE = U - f.d

where f is the frictional force acting

$\dfrac{1}{2}mv^2 = 43.75- \mu m g d$

$\dfrac{1}{2}\times 6 \times v^2 = 43.75- 0.3\times 6 \times 9.8 \times 0.5$

$v= \sqrt{11.643}$

v =3.41 m/s

4 0

4 years ago

Deduced hydrochloric acid is a strong acid ​

Deduced hydrochloric acid is a strong acid