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natali 33 [55]
3 years ago
8

The wavelength of 10^15-Hz light is:

Physics
1 answer:
Vanyuwa [196]3 years ago
5 0

Answer:

D.300nm

Explanation:

Wavelength = Speed of light / Frequency of light.....

where the speed of light is...(3 × 10^8)

Wavelength = (3 × 10^8)/(1 × 10^15)

Wavelength = 3 × 10^-7

;Wavelength = 300 × 10^-9

Hence its....300 nm

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A speeder passes a stationary police officer at a constant speed of 45 m/s. The police officer
weqwewe [10]

Answer:

a) 9

b) 45

I am not sure of the b part though :)

Explanation:

a) a= v /t  

  t= 45/5

    = 9

b) intial v= 0 t=9 s a= 5

5x 9 = 45

6 0
3 years ago
Que es la virtud para aristoteles
neonofarm [45]
Can you write in English so I can help you
7 0
3 years ago
Are the units of the formula ma = mv2/2 dimensionally consistent? Select the single best answer.
Vesnalui [34]

To solve the problem we will simply perform equivalence between both expressions. We will proceed to place your units and develop your internal operations in case there is any. From there we will compare and look at its consistency

ma = \text{Mass}\times \text{Acceleration}

ma = kg \cdot \frac{m}{s^2}

At the same time we have that

\frac{1}{2}mv^2 = \text{Mass}\times \text{Velocity}^2

\frac{1}{2}mv^2 = kg ( \frac{m}{s})^2

\frac{1}{2}mv^2 = kg \cdot \frac{m^2}{s^2}

Therefore there is not have same units and both are not consistent and the correct answer is B.

5 0
4 years ago
The figure below is a graph of net force vs. the acceleration of an object. Use a graph to determine the mass of the object.
kotegsom [21]

Answer:scattered plot

Explanation:

6 0
3 years ago
Find the frequency of a tuning fork that takes2.50×10−3s to complete one oscillation.
maksim [4K]

The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.

Frequency = 1/time period of the oscillation

Frequency of the tuning fork = 1/time period

                                                   =1/2.50×10⁻³

                                                   =400 Hz

Thus the frequency of a tuning fork comes out to be 400 Hz.

Learn more about frequency here, refer to the link;

brainly.com/question/14316711

#SPJ1

6 0
2 years ago
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