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2 years ago

PLEASE HELP I'LL GIVE BRAINLYIST

Mathematics

2 answers:

velikii [3]2 years ago

7 0

Answer: 2y=3/2 x is variable

Step-by-step explanation:

You will have to add the 4y plus the 3 and the rectangle being halved diagonle.so you will need to 27y and divide the variable and answer because it is timed I am here .

irinina [24]2 years ago

3 0

Answer:

4y^{2}+3y

Step-by-step explanation:

First you need to distribute the values.

(4y+3)(2y) Using the "Rainbow Method" to multiply the polynomials

You Should get

8y^{2}+6y

Since this is the area of the rectangle and we need to find the area of the shaded region you need to dived 8y^{2}+6y in half because the shaded region is half of the rectangle.

8y^{2}+6y/2

Doing this you will get

4y^{2}+3y

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What is -9x-(2x/-3) When x equals 7

yuradex [85]

$-9x- \frac{2x}{-3}$

$-9*(7) - \frac{2*7}{-3}$

$9*7 = 63$

$\frac{2*7}{-3} = \frac{14}{-3}$

Apply the fraction rule : $\frac{a}{-b} = - \frac{a}{b}$

$= - \frac{14}{3}$

$-63-( -\frac{14}{3} )$

Apply rule - ( - a) = a

$-63+ \frac{14}{3}$

Convert element to fraction :

$63 = \frac{63}{1}$

$-\frac{63}{1} + \frac{14}{3}$

Find the LCD 1*3 = 3

$- \frac{63*3}{3}+ \frac{14}{3}$

$\frac{-3+63+14}{3} = \frac{-175}{3}$

Apply the fraction rule : $\frac{a}{-b} = - \frac{a}{b}$ 

$= - \frac{175}{3}$

hope this helps!

4 0

3 years ago

Evaluate the following polynomial. (32mn2 + 50m2n) - (10mn2 - 16m2n + 64).

zaharov [31]

I think the answer is 22mn2+66m2n-64 since there are no more like terms

7 0

3 years ago

Which one is the right answer

Jobisdone [24]

Answer: A. f(g(x)) =x and g(f(x))=x and f and g are inverses.

Step-by-step explanation:

A function g is the inverse of function f if

f(g(x)) = g(f(x))=x

Given: f(x)= x+4 , g(x) = x-4

f(g(x)) = f(x+4) = (x-4)+4

= x-4+4 = x

i.e. f(g(x)) =x

g(f(x))= g(x-4) = (x-4)+4 =x

i.e. g(f(x))=x

Hence, f(g(x)) =x and g(f(x))=x and f and g are inverses.

8 0

2 years ago

What's the value of 1/4 - 7/6

Anton [14]

The answer is -11/12

3 0

2 years ago

Find the indicated values, where g(t)=t^2-t and f(x)=1+x f(2g(1)

Darina [25.2K]

$g(t)=t^2-t\\\\f(x)=1+x\\\\f(2g(1))=?\\\\g(1)=\\_{\text{put t=1 to the equation of g(t)}}\\\\=1^2-1=1-1=0\\---------------\\2g(1)=2(0)=0\\\\f(2g(1))=\\_{\text{put x-0 to the equation of f(x)}}\\\\=1+0=1\\\\Answer:\ f(2g(1))=1$

8 0

3 years ago

Read 2 more answers