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3 years ago

6.Calculate the centripetal acceleration of the Earth towards the Sun. (r = 1.5 x 1011 m)

Physics

1 answer:

riadik2000 [5.3K]3 years ago

6 0

Given,

The radius of Sun, $r=1.5\times 10^{11}\ m$

To find,

The centripetal acceleration of the Earth towards the Sun.

Solution,

The centripetal acceleration of an object is given by the formula as follows :

$a=\omega^2 r$ ....(1)

Where

$\omega$ is angular velocity

First calculate the angular velocity.

$\omega=\dfrac{2\pi}{1\ \text{day}}\\\\=\dfrac{2\pi}{24\times 3600\ s}\\\\=7.27\times 10^{-5}\ s^{-1}$

Put all the values in formula (1)

$a=\omega^2 r\\\\=(7.27\times 10^{-5})^2\times 1.5\times 10^{11}\\\\=792.79\ m/s^2$

So, the centripetal acceleration of the Earth towards the Sun is $792.79\ m/s^2$ .

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3 years ago

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3 years ago

5) [Honors]A seagull, ascending straight upward at 5.2 m/s, drops a shell when it is 12.5m above the ground. (A)

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Answer:

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3 years ago

Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed

I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

$\overrightarrow{L}=constant$

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