Answer:
b) farther
Explanation:
The range of the bullet shot horizontally just above the horizontal ground is given as;
where;
θ is the angle of projection with the horizontal ground = 0
R₁ = 0
The range of the bullet shot at an angle of 30 degrees with the same initial velocity as the first bullet is given as;
Therefore, the second bullet will travel a horizontal distance that is farther
Answer:
6.49707626552 m/s
4.45147808359 m
1.46212197842 s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
The speed with which Sam releases the ball is 6.49707626552 m/s
The ball reaches a height of 2.3+2.15147808359 = 4.45147808359 m
Distance to his head from the maximum height is 4.45147808359-1.83 = 2.62147808359 m
Time taken to go down to his head is 0.731060989212 seconds from the maximum height
Time taken from the moment the ball left his head height = 0.731060989212+0.731060989212 = 1.46212197842 s
Answer:
9.42 m/s
Explanation:
a) Using Newton's law of motion formula:
The speed of the discus at release (v) is:
v = ωr; where r = radius of discus
diameter = 1.8 m, r = diameter / 2= 1.6 / 2 = 0.9 m
v = ωr = 10.47 * 0.9
v = 9.42 m/s
Answer:
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
Explanation:
From the law of equilibrium, ΣF = 0 and ΣM = 0.
Let R be the reaction at the knife edge. Since the weight of the rod and zinc load act downward, and we take downward position as negative
-32 N - 2 N + R = 0
-34 N = -R
R = 34 N
Also, let us assume the knife-edge is x cm from the zero mark. Taking moments about the weight and assuming the knife-edge is right of the weight of the rod. Taking clockwise moments as positive and anti-clockwise moments as negative,
-(45 - 25)2 + (x - 45)R = 0
-(20)2 + (x - 45)34 = 0
-40 = -(x - 45)34
x - 45 = 40/34
x - 45 = 1.18
x = 45 + 1.18
x = 46.18 cm
x ≅ 46.2 cm
The second knife-edge must be placed 46.2 cm from the zero mark of the rod.
Answer:
Gravitational potential energy,
Explanation:
Mass of an Egyptian pyramid,
It is placed 19 m above the surrounding ground, h = 19 m
We need to find the gravitational potential energy store in the pyramid. This energy is possessed by an object due to its position. It is given by :
So, the gravitational potential energy store in the pyramid is . Hence, this is the required solution.