The minimum value of the coefficient of static friction between the block and the slope is 0.53.
<h3>Minimum coefficient of static friction</h3>
Apply Newton's second law of motion;
F - μFs = 0
μFs = F
where;
- μ is coefficient of static friction
- Fs is frictional force
- F is applied force
μ = F/Fs
μ = F/(mgcosθ)
μ = (250)/(50 x 9.8 x cos15)
μ = 0.53
Thus, the minimum value of the coefficient of static friction between the block and the slope is 0.53.
Learn more about coefficient of friction here: brainly.com/question/20241845
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Hooke's Law
F = k. Δx
Δx = 30 cm = 0.3 m
200 = k . 0.3
the spring stretch for 100 N:
Answer:
In the order largest to smallest
Pc = Pb, Pa
Explanation:
Power = Energy expended/time
Pa = 2/2 = 1Watt
Pb = 10/5 = 2Watt
Pc = 2E-3/1E-3 = 2Watt
<span>U could compare them using the intensity
technique when bending waves are negligible in comparison with
quasi-longitudinal waves.</span>
