Answer:
The net force exerted by the two charges is 10.97 x 10⁻⁵ N along negative x-direction.
Explanation:
K=1/4πϵ0, where ϵ0=8.854×10−12C2
K = 9x10⁹
The electric force on point charge q₃ due to charge q₂ is
F₃₂ = kq₃q₂ / (1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 30.5x10⁻⁹) / (1.245)²
= 13,587.75 x 10⁻⁹ / 1.55
= 8.76629 x 10⁻⁵ N
The electric force on point charge q₃ due to charge q₁ is
F₃₁ = kq₃q₁ / (1.695 - 1.245)²
= (9x10⁹ * 49.5x10⁻⁹ * 10.0x10⁻⁹) / 0.2025
= 2.2000 x 10⁻⁵ N
The net electric force on point charge q₃ is
F₃ = -F₃₁ - F₃₂
= - 8.76629 x 10⁻⁵ N - 2.2000 x 10⁻⁵ N
= 10.97 x 10⁻⁵ N along negative x-direction
