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Simora [160]
2 years ago
13

What is the minimum value?

Mathematics
1 answer:
professor190 [17]2 years ago
4 0
Easy one....
58
There is no difficult explanation. It’s always the left end of the box and whisker plot.
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A radioactive substance decays exponentially. A scientist begins with 190 milligrams of a radioactive
worty [1.4K]

Answer: 65.1 (mg)

Step-by-step explanation:

y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}

6 0
3 years ago
Solve: x ÷ 0.6 = 8.9<br><br><br> 5.34<br><br><br> 9.5<br><br><br> 8.3<br><br><br> 0.07
Basile [38]

Answer: x = 0.6 ÷ 8.9 = 5.34

Step-by-step explanation:

5 0
3 years ago
25. If mVYX = 276° and m angle UVX = (4x - 5),
katovenus [111]

Answer:

22.25 or 22

Step-by-step explanation:

360-276+=84

4x-5=84

4x=89

x=22.25 or 22

6 0
3 years ago
420 presents in 15 hours at this rate how many presents does Santa deliver in 5 hours​
Nesterboy [21]

Answer:31500

Step-by-step explanation:hope it helps!

4 0
3 years ago
Read 2 more answers
What is the explicit rule for this geometric sequence? 4,45,425,4125,…
gregori [183]
You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

Given the geometric sequence:

4,\  \frac{4}{5} ,\  \frac{4}{25} ,\  \frac{4}{125} ,\ .\ .\ .

Common ratio is given by r= \frac{2nd\ term}{1st\ term} = \frac{ \frac{4}{5} }{4} = \frac{1}{5}

The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n


Case 2:

Given the geometric sequence:

4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .

Common ratio is given by r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5

The explicit rule of a geometric sequence is given by T_n=ar^{n-1}

Therefore, the explicit rule of the given sequence is T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n
4 0
3 years ago
Read 2 more answers
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