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Vesnalui [34]
3 years ago
14

The high temperature in Fairbanks, Alaska was 15.7 °F one day. That night, the temperature fell 38.4 degrees. What was the low t

emperature for the night? Enter your answer as a decimal in the box
Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

-22.7

Step-by-step explanation:

Since the temperature fell, that would means that it's was cooler outside.

Hotter = Temperature goes up

Colder = Temperature goes down

15.7 - 38.4 = -22.7

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Step-by-step explanation:

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2 years ago
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Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

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Differentiating with respect to x,

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Differentiating w. r. t x,

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Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

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Differentiating w. r. t. t,

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Differentiating w. r. t. p,

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Differentiating w. r. t. t,

\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})

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Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

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Ymorist [56]
V=5/4 ...
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