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pashok25 [27]
3 years ago
5

Which of the lines below is a line of symmetry?

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0

Which of the lines below is a line of symmetry?

A. Red

B. Yellow

C. Neither

<u>D. Both</u>

Stolb23 [73]3 years ago
4 0
Answer:

D

Explanation:

Both lines divide the image into equal halves.
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Help me ASAP for this question
Olenka [21]

Answer:

(5, 21)

Step-by-step explanation:

We check for a point where the y coordinate isn't four times the x coordinate.

7 0
3 years ago
If a 150 pound woman would receive 24 grams of a certain medicine. How many grams should a 120 pound woman receive?
kumpel [21]

With a problem like this, set up a proportion (like when making lemonade from a mix).


\frac{weight}{medicine} = \frac{weight}{medicine} is our proportion.


We fill in the the two weights and the 24 grams of medicine in the proportion and solve for the fourth piece not there.


\frac{150}{24} =\frac{120}{M}


We shorten medicine to M and we solve for M by cross multiplying.


150M = 2880


M = \frac{2880}{150} = 19.2 grams


The woman should get 19.2 grams of medicine.



7 0
3 years ago
.prove that cos (90-A).sinA + sin(90 - A).cosA = 1 ​
pav-90 [236]

Answer:

See Explanation

Step-by-step explanation:

cos (90-A).sinA + sin(90 - A).cosA = 1  \\  \\ LHS = cos (90-A).sinA + sin(90 - A).cosA \\  \\ = sinA.sinA + cosA.cosA\\  \\ = sin ^{2} A + cos^{2} A \\  \\  = 1 \\  \\=RHS\\\\ reason \\ cos (90- \theta) = sin \theta \\ sin (90- \theta) = cos \theta \\ sin ^{2}  \theta + cos^{2}  \theta = 1 \\  \\ thus \: proved \\

4 0
3 years ago
Solve for x (6/5) x-4=46
alukav5142 [94]
(6/5) x - 4 = 46

Add 4 to both sides

(6/5)x = 50


To get rid of (6/5) multiply the inverse number by both sides. Inverse number is (5/6)

x = 50 * 5/6

x = (125/3)


5 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
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