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Drupady [299]
2 years ago
11

please answer right ill give brainliest and if u just need the points please don't submit an answer just comment on the question

and ill make a whole other question where u can answer and get like 50 points but answer right I really need to get this done and lol his name is sweet t

Mathematics
1 answer:
BartSMP [9]2 years ago
4 0

Answer:

Bella saves more per chore than sweet T

Step-by-step explanation: t only earns 2 cents a chore and only had 10 in savings, ayooo bellas for the dub

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One leg of a right triangle has a length of 7 m. The other side have lengths that are consecutive integers. Find these lengths
Darina [25.2K]

Answer:

6 and 5

Step-by-step explanation:

Consecutive means that it is continuous, and since the triangle largest side (7) has to be less than the additive of two other sides. Therefore 6 and 5. Hope this helps.

4 0
2 years ago
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pleas help on the second ASAP it was due yesterday.. i dont even understand how to do any of it and i will give brainliest <3
aliya0001 [1]

Answer:

3x^{4}

Step-by-step explanation:

I suggest looking lessons on it online if you don't understand... It's hard to do your work especially if you don't understand it. Or if your online, go to past lessons or something.

6 0
2 years ago
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What are the length and width of the rectangle?<br> (picture included)
Marianna [84]

Answer:

a or c

Step-by-step explanation:

I don’t know ask for help sorry don’t blam this on me

6 0
2 years ago
which expressions are equivalent to the first one? I don't understand how to determine that so please explain. Thanks!​
coldgirl [10]

9514 1404 393

Answer:

  (a) -(x+7)/y

  (b) (x+7)/-y

Step-by-step explanation:

There are several ways you can show expressions are equivalent. Perhaps the easiest and best is to put them in the same form. For an expression such as this, I prefer the form of answer (a), where the minus sign is factored out and the numerator and denominator have positive coefficients.

The given expression with -1 factored out is ...

  \dfrac{-x-7}{y}=\dfrac{1(x+7)}{y}=\boxed{-\dfrac{x+7}{y}} \quad\text{matches A}

Likewise, the expression of (b) with the minus sign factored out is ...

  \dfrac{x+7}{-y}=\boxed{-\dfrac{x+7}{y}}

On the other hand, simplifying expression (c) gives something different.

  \dfrac{-x-7}{-y}=\dfrac{-(x+7)}{-(y)}=\dfrac{x+7}{y} \qquad\text{opposite the given expression}

__

Another way you can write the expression is term-by-term with the terms in alpha-numeric sequence (so they're more easily compared).

  Given: (-x-7)/y = (-x/y) +(-7/y)

  (a) -(x+7)/y = (-x/y) +(-7/y)

  (b) (x+7)/(-y) = (-x/y) +(-7/y)

  (c) (-x-7)/(-y) = (x/y) +(7/y) . . . . not the same.

__

Of course, you need to know the use of the distributive property and the rules of signs.

  a(b+c) = ab +ac

  -a/b = a/(-b) = -(a/b)

  -a/(-b) = a/b

__

<u>Summary</u>: The given expression matches (a) and (b).

_____

<em>Additional comments</em>

Sometimes, when I'm really stuck trying to see if two expressions are equal, I subtract one from the other. If the difference is zero, then I know they are the same. Looking at (b), we could compute ...

  \left(\dfrac{-x-7}{y}\right)-\left(\dfrac{x+7}{-y}\right)=\dfrac{-y(-x-7)-y(x+7)}{-y^2}\\\\=\dfrac{xy+7y-xy-7y}{-y^2}=\dfrac{0}{-y^2}=0

Yet another way to check is to substitute numbers for the variables. It is a good idea to use (at least) one more set of numbers than there are variables, just to make sure you didn't accidentally find a solution where the expressions happen to be equal. We can use (x, y) = (1, 2), (2, 3), and (3, 5) for example.

The given expression evaluates to (-1-7)/2 = -4, (-2-7)/3 = -3, and (-3-7)/5 = -2.

(a) evaluates to -(1+7)/2 = -4, -(2+7)/3 = -3, -(3+7)/5 = -2, same as given

(b) evaluates to (1+7)/-2 = -4, (2+7)/-3 = -3, (3+7)/-5 = -2, same as given

(c) evaluates to (-1-7)/-2 = 4, different from given

3 0
2 years ago
W = zh - 6zk². Solve for z<br>(preferred with steps)​
8_murik_8 [283]

Answer:

           w

z =   ------------

         h - 6k²

Step-by-step explanation:

w = zh - 6zk²

zh - 6zk² = w

           w

z =   ------------

         h - 6k²

8 0
2 years ago
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