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mrs_skeptik [129]
2 years ago
5

PLEASE HELP!!!

Mathematics
1 answer:
Anna35 [415]2 years ago
5 0
I don’t quite understand your question? it had a slope of what?
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PLEASE HELP 4 QUESTIONS 90 POINTS
kondor19780726 [428]

1.  n^2 -8n +16 = 25

Subtract 25 from both sides

n^2 - 8n + 16 - 25 = 0

Simplify

n^2 - 8n - 9 =0

Factor

(n-9)(n+1) = 0

Solve for n

n-9 = 0, n = 9

n+1 = 0, n = -1

Solution: 9,-1


2. C = b^2/25

Multiply both sides by 25:

25c = b^2

Take square root of both sides

b = +/-√25c

Simplify:

b = 5√C, -5√C


3. d = 16t^2 +12t

subtract d from both side:

16t^2 + 12t -d =0

Use quadratic formula to solve:

t = (3 +/-√(9-4d))/8


4. 5w^2 +10w =40

Subtract 40 from both side:

5w^2 + 10w -40 = 0

Factor:

5(w-2)(w+4)=0

Divide both sides by 5:

(w-2)(w+4)=0

Solve for w:

w-2 = 0, w = 2

w+4=0, w = -4

Solution: 2,-4



4 0
3 years ago
Read 2 more answers
The Garcia family started the day with 2 gallons of milk. They drank 111 quart of milk for breakfast and 3 pints for lunch.
irina1246 [14]
3 pints

There are 8 pints of milk in 1 gallon. There is also 4 quarts in 1 gallon. So each quart is 2 pints.
After breakfast they had 3 quarts of the original gallon left since 4 - 1 = 3.
3 quarts is the same as 6 pints. They drank 3 pints at lunch. This means 6 - 3 = 3. After lunch, there were 3 pints left.
6 0
2 years ago
6. If the average temperature in February was 55°F arch was 64°F April was 74°F, and Ma was 85°F men which month had the smalles
mylen [45]
The month of February has the smallest gain in average temperature over the previous month?????
3 0
3 years ago
A box contains five keys, only one of which will open a lock. Keys are randomly selected and tried, one at a time, until the loc
Schach [20]

Answer:

Step-by-step explanation:

4 0
3 years ago
The area of rectangular field is 1440 sq meters and perimeter is 152 metre. Out of length or breadth which one is to be decrease
Arturiano [62]

Answer:

If Length is decreased by 10% then it would become a square.

Step-by-step explanation:

Given:

Area of Rectangular field = 1440 sq. m

Perimeter = 152 m.

We need to find which one needs to be decreased by what percentage to make it a square.

Solution:

Let length be denoted by 'l'.

Also Let width be denoted by 'w'.

Now we know that Area of rectangular field is given by Length times width.

framing in equation form we get;

l\times w = 1440 \ \ \ \ equation\ 1

Also we know that Perimeter of rectangular field is given by 2 times sum of  Length and width.

framing in equation form we get;

2(l+w) =152\\\\l+w =\frac{152}{2}\\\\l+w=76\\\\l=76-w \ \ \ \ equation \ 2

Now Substituting equation 2 in equation 1 we get;

l\times w =1440\\\\(76-w)w=1440\\\\76w-w^2=1440\\\\w^2-76w+1440 =0

Now we will find the root by factorizing the same we get;

w^2-36w-40w+1440=0\\\\w(w-36)-40(w-36)=0\\\\(w-36)(w-40) =0 \\

Now solving for each to find the value of 'w' we get;

w-36 =0\\\\w=36\\\\also \\\\w-40=0\\\\w=40

So We can say that;

Width = 36 m and Length = 40 m

Now we need to find out of length or breadth which one is to be decreased by what percentage to make it a square.

We know that square has all sides same.

So from the data we found we can say that if length is decreased by 4 then length and breadth(width) both will be equal.

So to find percentage decreased we will divide length to be decreased by total length and then multiply by 100.

framing in equation form we get;

percentage decreased = \frac{4}{40}\times 100 = 10\%

Hence If Length is decreased by 10% then it would become a square.

6 0
3 years ago
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