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mrs_skeptik [129]
3 years ago
5

PLEASE HELP!!!

Mathematics
1 answer:
Anna35 [415]3 years ago
5 0
I don’t quite understand your question? it had a slope of what?
You might be interested in
Equation 1: -4x + y = 6
tensa zangetsu [6.8K]

Answer:

<h2>B</h2>

Step-by-step explanation:

y in equation 1, since you just

-4x + y = 6

add 4x to both sides to get

y = 4x + 6

while for the rest of the variables in both equations, you need at least two steps

Thus, the answer is B

6 0
3 years ago
Read 2 more answers
Somenone help im faling horribly there is two qestion I need help on any one know both
Crazy boy [7]
C = 2πr
C = 2(3.14)(2.5)
C = 15.7 = 16 cm is your answer.

282.6 m = πD
282.6 m = (3.14)D
282.6 m/3.14 = 3.14/3.14 x D
90 m = D
90 meters is the diameter.

hope this helps you!!!
7 0
3 years ago
The mean weight of trucks traveling on a particular section of I-475 is not known. A state highway inspector needs an estimate o
kaheart [24]

Answer:

The 95 percent confidence interval for the population mean is between 14.736 tons and 16.864 tons.

Step-by-step explanation:

We have the population's standard deviation, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96*\frac{3.8}{\sqrt{49}} = 1.064

The lower end of the interval is the sample mean subtracted by M. So it is 15.8 - 1.064 = 14.736 tons

The upper end of the interval is the sample mean added to M. So it is 15.8 + 1.064 = 16.864 tons

The 95 percent confidence interval for the population mean is between 14.736 tons and 16.864 tons.

4 0
3 years ago
A trader claims that the proportion of stocks that offer dividends is different from 0.14. If the trader wants to conduct a hypo
Korvikt [17]

Answer:

The correct option is;

Two-tailed test

Step-by-step explanation:

From the interpretation of the question statement, the trader wants to conduct a hypothesis test on the trader's claim that the proportion of stocks that offer dividends is different from 0.14

Given that the difference is hypothesized, then the null hypothesis, H₀ and the alternative hypothesis, H₁ should be written as follows;

H₀: Null hypothesis (no difference, or no change)

H₁: μ ≠ μ₀ which is hypothesizing  difference which is known as a two-tailed test

The confidence level is then selected and the test statistic is calculated

6 0
3 years ago
Problem1 The behavior of a physical system can be described by the following first order differential equation: dy/dt=2y +t^2
daser333 [38]

Answer:

y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}.

Step-by-step explanation:

Using first order linear differential equation:

\dfrac{\mathrm{d} y}{\mathrm{d} t} = 2y + t^2

\frac{\mathrm{d} y}{\mathrm{d} t} - 2y =t^2

finding integrating factor:

I.F = e^{\int -2dt}

I.F =e^{-2t}

now,

y = \dfrac{1}{IF}(\int t^2dt+ c )

y = \dfrac{1}{e^{-2t}}(\int t^2dt+ c )

y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}

hence the solution is

y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}

8 0
4 years ago
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