Total cost for tiles and paints is $924.
Step-by-step explanation:
We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.
The paint will be required for 4 walls and ceiling.
Let us find area of walls and ceiling.
Therefore, the area of walls and ceiling is 1410 square meters.
Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,
Therefore, the total painting cost is $564.
Tiles will be required for floor. Let us find the area of floor.
Given: 1m squared floor tiles costs $3. So,
Therefore, the total cost for tiles is $360.
Now let us find combined total cost of tiles and paint.
Therefore, the combined total cost of tiles and paint is $924.
Step-by-step explanation:
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Answer:
x = 62
Step-by-step explanation:
x and 118 form a linear pair (added up, they both equal 180 degrees)
So, 180-118 = 62 which is the measurement of x
Answer: the company should invest $12191 each week
Step-by-step explanation:
The amount that the company needs is $5,400,000
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the weekly payments.
a represents the amount that the company needs
r represents the rate.
n represents number of weekly payments. Therefore
a = 5,400000
There are 52 weeks in a year
r = 0.079/52 = 0.0015
n = 52 × 14 = 728
Therefore,
P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]
5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]
P = 5400000/{2.98 -1}/[0.0015(2.98)]
P = 5400000/(1.98/0.00447)
P = 5400000/442.95
P = $12191
A sequence of operations that will get you to the solution is ...
... d. multiply each side by-5, add 25 to each side
_____
That is not the only correct sequence of operations. However the other ones listed here are incorrect ways to get to x = -10.
You can do whatever multiplication and addition you like to each side of the equation, but if those operations are poorly chosen, they will make finding the solution more difficult.
