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vlabodo [156]
3 years ago
14

Hey guys! what’s up :p

Mathematics
2 answers:
Triss [41]3 years ago
8 0

Answer:

hi

Step-by-step explanation:

inn [45]3 years ago
6 0

Answer:

hello

my friend

good morning

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What is the value of n in the proportion below n/28 = 4/7​
butalik [34]

n is 16

\frac{n}{28}  =  \frac{4}{7}  \\  n = \frac{4 \times 28}{7}  = 16

good luck

3 0
3 years ago
Read 2 more answers
Tia and her five friends are going to the ice skating rink. Each person $5 for admission and $5 for food. Write and evaluate a n
ozzi

Where C = Cost and P = People


C = 2(5p)


In the context of Tia and her five friends:


C = 2(5*6) = 2(30) = 60

C = 60


The cost for Tia and her five friends to be admitted to ice skate and eat is 60$, and the equation to calculate this is C = 2(5p).

4 0
3 years ago
Please help solve 6x < 42
tensa zangetsu [6.8K]

6x<42

Divide 6 by both sides

x<7


7 0
4 years ago
5. What is an equation of the line in slope-intercept form?
777dan777 [17]

Answer:

y = (2/7)x -12

Step-by-step explanation:

y = mx + b is the standard form of an equation of a straight line in which m is the slope and b is the y-intercept (the value of y when x is zero)..

<u>m</u>=(2/7) and <u>b</u> = -12

y =   <u>m</u>x  + <u>b</u>

y = (<u>2/7</u>)x <u>-12</u>

8 0
3 years ago
What is the y cordinate of the solution<br>solve 8 and 9<br>​
Flauer [41]

Answer:

8) The y coordinate of the solution: 4

9) Average of change from x = 2 to x = 4: 11

Step-by-step explanation:

8)

y = 2x + 2

y = x^2 + 3

So

x^2 + 3 = 2x + 2

x^2 - 2x + 3 - 2 = 0

x^2 - 2x + 1 = 0

(x - 1)^2 = 0

x - 1 = 0

x = 1

Plug in x = 1 into either those 2 equations to find y

y = 2(1) + 2 = 4

or

y = (1)^2 +  3 = 1 + 3 = 4

Answer:

The y coordinate of the solution is 4

9)

p(x) = x^2 + 5x - 2

p(2) = 2^2 + 5(2) - 2 = 4 + 10 - 2 = 12

p(4) = 4^2 + 5(4) - 2 = 16 + 20 - 2 = 34

Average of change from x = 2 to x = 4:

[p(4) - p(2)]/[(x(4) - x(2)] = (34 - 12)/(4-2) = 22 /2 = 11

Answer:

Average of change from x = 2 to x = 4 :11

4 0
3 years ago
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