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2 years ago

Thanks for help ✨pppp

Mathematics

2 answers:

Elan Coil [88]2 years ago

7 0

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goldfiish [28.3K]2 years ago

4 0

Answer:

Step-by-step explanation:

In similar triangles, corresponding angles will be in the same ratio

EA = DA - DE = 10 - 5 =5

$\dfrac{EA}{DE}=\dfrac{BA}{CB}\\\\\\\dfrac{5}{5}=\dfrac{6}{x+3}\\\\1 =\dfrac{6}{x+3}$

Cross multiply,

x +3 = 6

Subtract 3 from both sides

x = 6 - 3

x = 3

x +1 = 3+ 1 = 4

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Find the distance between the points (8,1) and (2,10). Round decimals to the nearest tenth.

miss Akunina [59]

The nearest distance between the points (8,1) and (2,10) is 11 units, which is mentioned in and also calculated by using formula.

Step-by-step explanation:

The given is,

Two points are (8,1) (2,10)

Step: 1

By graphical method, refer the attachment,

First point (8,1)

The values of x=8 and y=1 noted in the graph

Second point (2,10)

The values of x=2 and y=10 noted in the graph

Now join the two points (8,1) and (2,10)

Measure the distance between two points, the distance is 11 units. Due to some error the value becomes 10.98 or 11.1 we need to convert the answer into nearest whole number.

( OR )

Step:1

By formula method,

Distance = $\sqrt{(x_{2} - x_{1} )^{2} +(y_{2} - y_{1} )^{2} }$ .....................(1)

Where,

(8,1) are ( $x_{1},y_{1}$ )

(2,10) are ( $x_{2},y_{2}$ )

From the equation,

= $\sqrt{(2 - 8 )^{2} +(10 - 1 )^{2} }$

= $\sqrt{(-6 )^{2} +(9 )^{2} }$

= $\sqrt{36 +81 }$

= $\sqrt{117}$

= 10.81665

≅ 11 ( Answer convert to the nearest tenth)

Distance = 11 units

Result:

The nearest distance between the points (8,1) and (2,10) is 11 units, which is mentioned in and also calculated by using formula.

5 0

3 years ago

A right triangle includes one angle that mesures 30 degrees. What is the measure of the third angle?

Airida [17]

The third angle is 60 degrees. A triangle has 180 degrees so 180-30-90=60

5 0

3 years ago

Read 2 more answers

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago

What is 5kg in the ratio of 7:3

cluponka [151]

Answer:

5000/750 = 20:3

Step-by-step explanation:

5kg = 5000g

5000:750 (divide by 10)

500:75 (divide by 5)

100:15 (divide by 5)

20:3

8 0

2 years ago

In circle o, the length of radius OL is 6 cm and the length

AlekseyPX

Answer:

14.2cm

Step-by-step explanation:

The diagram representing the circle and its attributes has been attached to this response.

As shown in the diagram;

The circle is centered at o,

The length of radius OL = 6cm

The length of the arc LM = 6.3cm

The angle MON = 75°

The angle LOM = θ

Remember that;

The length, L, of an arc is given by;

L = (θ / 360) x (2πr) -------------(i)

Where;

θ is the angle subtended by the arc

r = radius of the circle.

Using the formula in equation (i), let's calculate the angle θ subtended by arc LM as follows;

L = (θ / 360) x (2πr)

Where;

L = length of arc LM = 6.3cm

r = radius of the circle = length of radius OL = 6cm

Substitute these values into the equation to get;

6.3 = (θ / 360) x (2 x π x 6)

6.3 = (θ / 360) x (12 x π)

6.3 = (θ / 30) x (π) [Take π = 22/7]

6.3 = (θ / 30) x (22 / 7)

θ = $\frac{6.3*30*7}{22}$

θ = 60.14°

Therefore, the angle subtended by arc LM is 60.14°

Now, from the diagram,

The angle subtended by arc LMN is;

θ + 75° = 60.14° + 75° = 135.14°

Let's now calculate the length of arc LMN using the same equation (i)

L = (θ / 360) x (2πr)

Where;

L = length of arc LMN

θ = angle subtended by LMN = 135.14°

r = radius of the circle = length of radius OL = 6cm

Substitute these values into the equation;

L = (135.14° / 360°) x (2 x π x 6) [Take π = 22/7]

L = 14.15cm

Therefore, the length of arc LMN is 14.2cm to the nearest tenth.

6 0

3 years ago