What is the fastest way to solve the following question:

Mathematics

2 answers:

dedylja [7]2 years ago

5 0

Answer:

There are 6 more girls than boys

Step-by-step explanation:

boys :girls : total

2 3 2+3 = 5

There are 30 total students

30/5 = 6

Multiply each number by 6

boys :girls : total

2*6 3*6 5*6

12 18 30

There are 18 girls and 12 boys

18-12 = 6

There are 6 more girls than boys

Tcecarenko [31]2 years ago

5 0

Answer:

Answer is 6.

Step-by-step explanation:

I will now explain the fastest way to solve this. First off, the ratio is 2:3 so the first thing I do is combine that for 5, then do 30/5 for an answer of 6. Then, I multiply 6 for the ratio, which comes out as 12:18, 12 boys and 18 girls. 18-12=6, so there are 6 more girls than boys in the class.

You might be interested in

(√2)^3 <img src="https://tex.z-dn.net/?f=%20%28%5Csqrt%7B2%29%20%7B%3F%7D%5E%7B3%20%5C%5C%7D%20" id="TexFormula1" title=" (\s

Vedmedyk [2.9K]

$\sf \left(\sqrt{2}\right)^3\\\\\\\\\boxed{\sf \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}}\\\\\\\\\sf \left(2^{\frac{1}{2}}\right)^3\\\\\\\\\boxed{\sf\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc} }\\\\\\\\\sf \sf 2^{\frac{1}{2}\cdot \:3}\\\\\\\\\sf 2^{\frac{3}{2}}\\\\\\\\\sf 2^{\frac{3}{2}}=2^{1+\frac{1}{2}}\\\\\\\\\sf 2^{1+\frac{1}{2}}\\\\\\\\\boxed{\sf \mathrm{Apply\:exponent\:rule}:\quad \:x^{a+b}=x^ax^b}\\\\\\\\\sf$