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zvonat [6]
3 years ago
7

Pls help and show workings

Mathematics
1 answer:
andreev551 [17]3 years ago
8 0

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

<em>5x - 1 = 4x + 10</em>

<em>5x - 1 (+ 1) = 4x + 10 (+ 1)</em>

<em>5x = 4x + 11</em>

<em>5x (- 4x) = 4x (- 4x) + 11</em>

x = 11

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Which shows the following expression using positive exponents?
Hitman42 [59]

Answer:

1. option B is correct i.e., \frac{-3a^{7}b^3b^1}{15a^{2}}

2. option D is correct i.e., \frac{a^3b^4}{ab^2}.

3. option B is correct i.e.,  \frac{n^{10}}{16m^{6}}.

Step-by-step explanation:

1. Since the given equation is:

\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}

As we know that a^{-x}=\frac{1}{a^x}

So, the given equation can be represented as:

\frac{-3a^{7}b^3b^1}{15a^{2}}


2. Given equation is:

\frac{a^3b^{-2}}{ab^{-4}}

As we know that a^{-x}=\frac{1}{a^x}

so the given equation can be represented as:

\frac{a^3b^4}{ab^2}.


3.  Given equation is:

(\frac{4mn}{m^{-2}n^6})^{-2}

by using the properties a^{-x}=\frac{1}{a^x},

and a^x\times a^y=a^{x+y}

(\frac{4mn}{m^{-2}n^6})^{-2}

= (\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}

= (\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}

= (\frac{4n^{-5}}{m^{-3}})^{-2}

= \frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}

= \frac{n^{10}}{16m^{6}}.

which is option B.

5 0
3 years ago
Read 2 more answers
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4 0
3 years ago
X² + y² if x = 7 and y = 5. What is the solution to this??
Shtirlitz [24]

Hey there!

x^2 + y^2

= 7^2 + 5^2

= 7 * 7 + 5 * 5

= 49 + 25

= 74


Therefore, your answer should be: 74


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
1 year ago
Read 2 more answers
Use the Figure below to find the value of x
JulsSmile [24]

Answer:

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Step-by-step explanation:

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MakcuM [25]
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3 years ago
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