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3 years ago

Pls help and show workings

Mathematics

1 answer:

andreev551 [17]3 years ago

8 0

Answer: x = 11

Step-by-step explanation:

same as the last question, set them as equal and solve. here's my work:

5x - 1 = 4x + 10

5x - 1 (+ 1) = 4x + 10 (+ 1)

5x = 4x + 11

5x (- 4x) = 4x (- 4x) + 11

x = 11

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Which shows the following expression using positive exponents?

Hitman42 [59]

Answer:

1. option B is correct i.e., $\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. option D is correct i.e., $\frac{a^3b^4}{ab^2}$ .

3. option B is correct i.e., $\frac{n^{10}}{16m^{6}}$ .

Step-by-step explanation:

1. Since the given equation is:

$\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}$

As we know that $a^{-x}=\frac{1}{a^x}$

So, the given equation can be represented as:

$\frac{-3a^{7}b^3b^1}{15a^{2}}$

2. Given equation is:

$\frac{a^3b^{-2}}{ab^{-4}}$

As we know that $a^{-x}=\frac{1}{a^x}$

so the given equation can be represented as:

$\frac{a^3b^4}{ab^2}$ .

3. Given equation is:

$(\frac{4mn}{m^{-2}n^6})^{-2}$

by using the properties $a^{-x}=\frac{1}{a^x}$ ,

and $a^x\times a^y=a^{x+y}$

$(\frac{4mn}{m^{-2}n^6})^{-2}$

= $(\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}$

= $(\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}$

= $(\frac{4n^{-5}}{m^{-3}})^{-2}$

= $\frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}$

= $\frac{n^{10}}{16m^{6}}$ .

which is option B.

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Hey there!

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Therefore, your answer should be: 74

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

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