Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
D is the correct answer
x+5=10: subtract 5 from both sides the 5 will cancel out leaving x=5
x+5=10
-5 -5
x=5
Answer:
5
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
70÷14=5
5×3=15
So the ratio would be 70:15 which can be simplified to 14:3
1. 2√2
2. √5
3. 5√3
4. 10
5. 4√2
6. 3√5
7. 4√3
8. 5√5
9. 3√2
10. 3√3
11. 4
12. 6
13. 5√2
14. 2√3
