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Nimfa-mama [501]
3 years ago
14

Greenbaum Inc. sells a new product with a 2-year warranty. The company estimates that during the two years, the costs and relate

d probabilities are: Year 1: $20,000 (40%) and $30,000 (60%); Year 2: $30,000 (70%); $20,000 (30%).The company's effective interest rate is 5%. Calculate the estimated warranty liability using the expected cash flow method.
Business
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

$49,252

Explanation:

Calculation to the estimated warranty liability using the expected cash flow method.

Estimated warranty liability =[($20,000 x .4)+($30,000 x .6) x 0.95238]+ [($30,000 x .7)+($20,000x .3) x 0.90703]

Estimated warranty liability =[($8,000+$18,000)×0.95238]+[($21,000+$6,000)×0.90703

Estimated warranty liability =($26,000×0.95238)+($27,000×0.90703)

Estimated warranty liability =$24,762+$24,490

Estimated warranty liability =$49,252

Therefore the estimated warranty liability using the expected cash flow method is $49,252

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A company’s total monthly sales (in millions of dollars) t months from now are given by:
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Answer:

a) \frac{dS}{dt}=S'(t)= 2(0.5) t +3 = t+3

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e) This value represent the increase in the amount of sales in millions after t=4 months

Explanation:

For this case we have the following function for the sales

S(t) = 0.5 t^2 +3t -5

Part a          

For this case we want to find the derivate of S respect to t and we got:

\frac{dS}{dt}=S'(t)= 2(0.5) t +3 = t+3

Part b

For this case we want to find the value of S when t = 4 so if we replace we got:

S(4) = 0.5*(4^2) +3(4) -5=15 million

Part c

For this case we have the total sales $ 15 millions after t =4 months

Part d

For this case we just need to replace t=4 in the derivate and we got:

S'(4) = 4+3 = 7 million

Part e

This value represent the increase in the amount of sales in millions after t=4 months

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