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GenaCL600 [577]
3 years ago
9

What would the equation be for the sequence:

Mathematics
1 answer:
Ann [662]3 years ago
6 0
The answer is B because you have to do the opposite which means you have to subtract -9-2=-11
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A gymnastics school offered a special for enrollment where a new student could enroll for half the price after paying a $17.50 a
nata0808 [166]

Answer:

12 (p/2 + 17.50) = 750 equation can be used to get regular price of enrollment.

Step-by-step explanation:

So when a new student gets enrolled by paying a $17.50 application fee and gets a value of price halved at p/2

where p = regular price of enrollment

So in reality, for the student to be enrolled he/she must pay = (p/2) + $17.50 application fee to be able to get that special offer.

So Twelve new students enrolled, meaning they paid: 12 (p/2 + 17.50 application fee)

The amount they all paid is $750.

To get the regular price of enrollment from the price that included the application fees, the equation to use would be: 12 (p/2 + 17.50) = 750

8 0
3 years ago
Read 2 more answers
Select the correct answer from each drop-down menu. cos2x-cos4x/sin2x+sin4x cos2x+cos4x/sin2x-sin4x
Anastaziya [24]
I’m sorry I’m answering this to ask a question



Explanation:
8 0
3 years ago
I need a math problem for my 7th grade math teacher, can anybody help me please?
Lelu [443]

Answer:

Whats the problem? and what class (algebra...)

Step-by-step explanation:

4 0
3 years ago
Five more than a number is ten
Alja [10]

                                       <u>Number + 5  =  10</u>

Subtract  5  from each side:<em>  Number = 5</em>
5 0
3 years ago
EASY POINTS!! HELP AND ILL MARK YOU BRAINLIEST!!!!
natali 33 [55]

Answer: (6, -30)

Step-by-step explanation:

Substitute the points into the equation:

3.5 = -1/2(1^3) - 3(1) + 7 = 3.5: (1, 3.5) is on the graph.

-60.5 = -1/2 (9^2) -3(9) + 7 = -60.5: (9, -60.5) is on the graph.

-1 = -1/2 (-8^2) -3(-8) + 7 = -1. (-8, -1) is on  the graph.

-30 = -1/2(6^2) -3(6) + 7 = -29 (6, -30) is not on the graoh.

3 0
3 years ago
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