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3 years ago

Who want to argue I. know y'all bored

Mathematics

2 answers:

Nitella [24]3 years ago

8 0

Free Points I guess.....

aev [14]3 years ago

7 0

Answer:

Argue?

Step-by-step explanation:

How about we argue if you give me brainliest or not?

You might be interested in

Let f(x)=4x-1 and g(x)=2x^2+3. Perform each function operations and then find the domain.

Triss [41]

F(x) = 4x - 1
g(x) = 2x² + 3

1. (f + g)(x) = (4x - 1) + (2x² + 3)
(f + g)(x) = 2x² + 4x + (-1 + 3)
(f + g)(x) = 2x² + 4x + 2
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

2. (f - g)(x) = (4x + 1) - (2x² + 3)
  (f - g)(x) = 4x + 1 - 2x² - 3
(f - g)(x) = -2x² + 4x + 1 - 3
(f - g)(x) = -2x² + 4x - 2
Domain: {x|-∞ < x < ∞}, (-∞, ∞)
3. (g - f)(x) = (2x² + 3) - (4x - 1)
(g - f)(x) = 2x² + 3 - 4x + 1
(g - f)(x) = 2x² - 4x + 3 + 1
(g - f)(x) = 2x² - 4x + 4
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

4. (f · g)(x) = (4x + 1)(2x² + 3)
(f · g)(x) = 4x(2x² + 3) + 1(2x² + 3)
(f · g)(x) = 4x(2x²) + 4x(3) + 1(2x²) + 1(3)
(f · g)(x) = 8x³ + 12x + 2x² + 3
(f · g)(x) = 8x³ + 2x² + 12x + 3
Domain: {x| -∞ < x < ∞}, (-∞, ∞)

5. $(\frac{f}{g})(x) = \frac{4x - 1}{2x^{2} + 3}$
Domain: 2x² + 3 ≠ 0
- 3 - 3
2x² ≠ 0
2 2
  x² ≠ 0
x ≠ 0
(-∞, 0) ∨ (0, ∞)

6. $(\frac{g}{f})(x) = \frac{2x^{2} + 3}{4x - 1}$
Domain: 4x - 1 ≠ 0
+ 1 + 1
4x ≠ 0
4   4
x ≠ 0
  (-∞, 0) ∨ (0, ∞)

6 0

3 years ago

.please hellpppppppp

Aleksandr-060686 [28]

Answer:

Can you take the pic a little more I can't see all the question pls

5 0

2 years ago

Xavier is a salesperson who is paid a fixed amount of $455 per week. He also earns a commission of 3% on the sales he makes. If

Lunna [17]

575 - 455 = $120 (amount of commissions he'll have to earn.
To make $120 in commissions, his sales would have to be $120/.03 =
$4,000.00

5 0

3 years ago

Read 2 more answers

What is the distributive property of 6x8-6x5

topjm [15]

Answer:

6(8-5)

Step-by-step explanation:

8 0

3 years ago

A unicorn’s favorite food is marshmallows. They can find other food resources, but marshmallows are their absolute favorite. Usi

Tpy6a [65]

Answer:

69813.33 marshmallow

the calories required (i.e 10,920,800 ) is greater than the energy provided (i.e 7,500,000) hence the 2 unicorns cannot survive

Step-by-step explanation:

Given:

Unicorn weights = 440 kg

Marshmallow weighs = 0.5 grams

Unicorn needs = 34 calories/kg of body weight/day

Marshmallow offers = 3 calories/gram

Calories required by Unicorn in a week

= Calories needed × Weight of unicorn × Total days in a week

= 34 × 440 × 7

= 104,720 calories

Now,

Marshmallows required = $\frac{\textup{Calories required}}{\textup{Energy offered by marshmallow}}$

= $\frac{\textup{104,720}}{\textup{3}}$

= 34906.67 grams

Therefore,

the number of marshmallows required = $\frac{\textup{Mass of marshmallow required}}{\textup{Mass of marshmallow}}$

= $\frac{\textup{34906.67}}{\textup{0.5}}$

= 69813.33 marshmallow

b) Total calories provided by the marshmallow

= 5,000,000 × 0.5 × 3

= 7,500,000 calories

and,

calories required by 2 unicorns in an year

= weight of 2 unicorn × calories needed × number of days in an year

= 2 × 440 × 34 × 365

= 10,920,800

Since,

the calories required (i.e 10,920,800 ) is greater than the energy provided (i.e 7,500,000) hence the 2 unicorns cannot survive

5 0

3 years ago

Who want to argue I. know y'all bored​

Who want to argue I. know y'all bored