Question

A juice can is 16 cm tall and has a diameter of 9 cm. The ends of the can are tin and the body is cardboard.

Answer 1

Answer:

I'll setup the problem and you can do the calculations

Step-by-step explanation:

a.

$V = \pi( {D}^{2} \div 4)H$

V = volume; D = diameter; H = height of can

b.

Area of the Tin is the total area of the 2 Tin circles

one circle's area A is

$A = \pi {D}^{2} \div 4$

A = area; D = diameter

calculate A

Then multiply by 2

c.

The area of the cardboard is the circumstance of the circle

times the height

$SA = \pi DH$

d.

add answers from b and c