Answer: D. 3.2
Step-by-step explanation:
Given : In parallelogram LMNO,
LM = 4.12, MN = 4, LN = 5, and OM = 6.4.
Diagonals and intersect at point R.
We know that diagonals of a parallelogram bisect each other.
Since R is the intersection point of both diagonals.
⇒R is the mid point of OM.
Thus OR=
Therefore, OR=3.2
The answer is D as it can be rewritten as -((y^2)/5)-(8/5)=x. Solving for the x-intercepts you get -((y^2)/5)-(8/5) = 0 as you want to find the y values when x is zero. Solving for y you get: (y^2)/5)+(8/5) = 0 => (y^2)/5)=-(8/5) => y^2=-8 => y = plus or minus sqrt(-8). The first problem is that you have 2 x intercepts which already makes it not a function and second sqrt(-8) is an imaginary number making the solution not a real number.
Answer:
10
Step-by-step explanation:
This is the answer because:
1) First, insert all the numbers into the expression
Expression: I -2(2) + -3(2) I
2) Next, do -2 x 2 and -3 x 2
-2 x 2 = -4
-3 x 2 = -6
3) Then, do -4 + -6
-4 + -6 = -10
4) Finally, the absolute value of -10 is 10
Therefore the answer is 10
Hope this helps!
Answer:
52
Step-by-step explanation:
Let x represent the smallest of the three numbers. Then the other two are (x+2) and (x+4). Their sum is ...
x + (x+2) +(x+4) = 162
3x = 156 . . . . . . . . . . . .subtract 6
x = 156/3 = 52
The smallest of the three numbers is 52.
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I like to work problems like this by considering the average number. Here, the average of the three numbers is 162/3 = 54, the middle number of the three. Then the smallest of the three consecutive even numbers is 2 less, or 52.
