Answer:
Greater than (>)
Step-by-step explanation:
Last week, Jason ran 26.1 miles.
He wants to run further this week.
<u>Distance Run this week</u>
- 2.4 miles to the park,
- Four times around the park= 4p (if distance around the park is p miles)
- 2.4 miles back from the park.
Total Distance this week =2.4+4p+2.4
Since his distance this week is going to be greater than the total distance covered last week (26.1 miles), we then have:
Total Distance covered this week > Total Distance Last week
Jason should use the greater than inequality sign.
Step-by-step explanation:
the volume of this object is the sum of the volume of the 2 blocks.
the large block is a cube of 4×4×4 = 64 ft³
the small block is 1×1×2 = 2 ft³
so, in total, he can fit 64+2 = 66 ft³ of plaster into the mold.
Answer:
1. Multiples
2. factors
3.multiples
4.factor
5.factor
Step-by-step explanation:
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:
So, the number of ways to select exactly 3 aces is:
Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:
On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:
The greatest common factor is found by finding the product of common primes.
91=7*13, 104=2*2*2*13 so the gcf of 91 and 104 is 13. Since the highest power of x and y in both terms is 1, the hcf for the variables is just xy
13xy
