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Fantom [35]
3 years ago
13

9n + 1 word phrase algebraic expression

Mathematics
2 answers:
nata0808 [166]3 years ago
8 0
Nine n plus 1 word phrase--
Svetradugi [14.3K]3 years ago
7 0

Answer:

The word phrase of the expression 9n+1 is:

Nine times n plus one

Step-by-step explanation:

We are given a algebraic equation:

9n+1

we have to find the word phrase of this expression

9n means Nine times n

9n+1 means Nine times n plus one

Hence,

The word phrase of the expression 9n+1 is:

Nine times n plus one

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Answer:

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Step-by-step explanation:

they ran 5 and 2 and half hour

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3 years ago
PLEASE ANSWER FAST IM FAILING MATH!!!
posledela

Answer:

Step-by-step explanation:

From the figure attached,

Point B has been dilated to form point B'.

B(3, 1) → B'(6, 2)

          → B'[(2 × 3), (2 × 1)]

Since rule for the dilation of a point (x, y) by a factor of k is,

B(x, y) → B'(kx, ky)

By comparing the coordinates k = 2 is the scale factor by which the point B has been dilated about the origin.

Therefore, other vertices of the quadrilateral will be,

A(-2, 3) → A'(-4, 6)

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3 years ago
How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

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3 years ago
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Verdich [7]
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Answer:

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Step-by-step explanation:

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