Write the equation of the line passing through the points (-4,7) and (-7,4)

2 answers:

8 0

The answer is: 1

To find the equation I subtract 4-7 and -7-(-4). I receive the answer of -3/-3.

-3/-3 simplifies 3/3 which is equal to 1.

So the equation is 1? I think this is the correct answer

Mnenie [13.5K]3 years ago

5 0

Answer:

y=x+11

Step-by-step explanation:

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Write the equation of the line that passes through the given points (-6, 0) and (0, 3)

Tomtit [17]

Answer:

Step-by-step explanation:

Put (-6,0) and (0,3) into a table of values

form of the equation: mx+b

x -6 0

y 0 3

3/-6=-0.5 (m)

3=b (the value of y when x=0)

equation: y=0.5x+3

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3 years ago

What is the value of c so that -12 and 12 are both solutions of x^2-c=108?

murzikaleks [220]

Answer:

c=36

Step-by-step explanation:

Because $x^2-c=108$ can be rewritten as $x^2-c-108=0$ , finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that $(+-)12^2-c-108=0$ .
Because $12^2=(-12)^2=144$ , we must find c so that $144-c-108=0$ .
Because $144-108=36$ , c=36.
To check, replace c=36 in the initial equation, and check it is a solution for x=(+-)12.