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Leokris [45]
3 years ago
7

Add 3965 + 4387 PLEASE SHOW ALL WORK AND STEPS. THANK YOU

Mathematics
2 answers:
torisob [31]3 years ago
3 0

Answer:

8342

Step-by-step explanation:

3965 + 4387

 3965

+4387

Add 5 and 7

12

The 1 in ten becomes a digit in the tens place

Add 1, 6, and 8

15

The 1 in ten becomes a digit in the hundreds place

Add 1, 9, 3

13

The 1 in ten becomes a digit in the thousands place

Add 3, 4, and 1

8

Answer:

8342

OleMash [197]3 years ago
3 0

Answer:

8352

Step-by-step explanation:

Use column method:

  3965

+ 4387

=  <u>8352</u>

(Add the numbers vertically)

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Given the system of equations presented here:
Nata [24]
2x + 4y = 14
4x + y = 20......multiply by -4
----------------
2x + 4y = 14
-16x - 4y = -80 (result of multiplying by -4)
---------------add
-14x = -66....as u can see, ur y's cancel out

so ur answer is : 1st answer choice <==

** and just so u know, u could have multiplied the 1st equation by -2, and it would have cancelled out ur x's
6 0
3 years ago
9% of 750............................
babunello [35]
67.5 is your answer.
8 0
3 years ago
Read 2 more answers
HELPPP!!!!<br><br> What is one solution?<br> Eliminate any extraneous solutions.
olga nikolaevna [1]

Answer:

The correct answer is x= 4/5 because you cannot take the root of a negative number

4 0
3 years ago
Hello, I need help with this math problem please
Marina86 [1]

Answer:

4c^2+7c-5=0

4c^2+7c=5

4c^2+7c=5

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4 0
3 years ago
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Find the probability that the mean annual preciptiation will be between 32 and 34 inches. variable is normally distributed
liq [111]
Supposing, for the sake of illustration, that the mean is 31.2 and the std. dev. is 1.9.

This probability can be calculated by finding z-scores and their corresponding areas under the std. normal curve.  
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The area under this curve to the left of z = -------------------- = 1.47 (for 34 in)
                                                                           1.9
                                                                      32 in - 31.2 in
and that to the left of 32 in   is               z = ---------------------- = 0.421
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Know how to use a table of z-scores to find these two areas?  If not, let me know and I'll go over that with you.


My TI-83 calculator provided the following result:

normalcdf(32, 34, 31.2, 1.9) = 0.267  (answer to this sample problem)

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